Sort the odd.js

// Task
// You will be given an array of numbers. You have to sort the odd numbers in ascending order while leaving the even numbers at their original positions.

// Examples
// [7, 1]  =>  [1, 7]
// [5, 8, 6, 3, 4]  =>  [3, 8, 6, 5, 4]
// [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]  =>  [1, 8, 3, 6, 5, 4, 7, 2, 9,



function sortArray(array) {
    // Return a sorted array.
    const oddNumbers = array.filter(num => num % 2 !== 0).sort((a, b) => a - b);
    return array.map(num => (num % 2 !== 0 ? oddNumbers.shift() : num));
  }