389. Find the Difference

You are given two strings s and t.

String t is generated by random shuffling string s and then add one more letter at a random position.

Return the letter that was added to t.

Example 1:

Input: s = "abcd", t = "abcde"
Output: "e"
Explanation: 'e' is the letter that was added.
Example 2:

Input: s = "", t = "y"
Output: "y"
 

Constraints:

0 <= s.length <= 1000
t.length == s.length + 1
s and t consist of lowercase English letters.

Solution :
//Java
//Solution 1 :

class Solution {
    public char findTheDifference(String s, String t) {
        int sum=0;
        if(s.length()>t.length()){
        for(int i=0;i<t.length();i++){
            sum-=t.charAt(i);
        }
        for(int i=0;i<s.length();i++){
            sum+=s.charAt(i);
        }
        return (char)sum;
        }
        else{
            for(int i=0;i<t.length();i++){
            sum+=t.charAt(i);
        }
        for(int i=0;i<s.length();i++){
            sum-=s.charAt(i);
        }
        return (char)sum;
        }
    }
}




//Solution 2 :

class HelloWorld {
    public static void main(String[] args) {
        //Scanner a=new Scanner(System.in);
        String s="abcd";
        String t="abcde";
        int sum=0;
        if(s.length()>t.length()){
        for(int i=0;i<t.length();i++){
            sum-=t.charAt(i);
        }
        for(int i=0;i<s.length();i++){
            sum+=s.charAt(i);
        }
         System.out.println((char)sum);
        }
        else{
            for(int i=0;i<t.length();i++){
            sum+=t.charAt(i);
        }
        for(int i=0;i<s.length();i++){
            sum-=s.charAt(i);
        }
         System.out.println((char)sum);
        }
    }
}