Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama"
is a palindrome."race a car"
is not a palindrome.Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
判断一个字符串是不是回文串。
字符串的回文判断问题,由于字符串可随机访问,故逐个比较首尾字符是否相等最为便利,即常见的『两根指针』技法。
两步走:
- 找到最左边和最右边的第一个合法字符(字母或者字符)
- 一致转换为小写进行比较
public class Solution {
public boolean isPalindrome(String s) {
if (s == null || s.trim().isEmpty()) {
return true;
}
int l = 0, r = s.length() - 1;
while (l < r) {
if(!Character.isLetterOrDigit(s.charAt(l))) {
l++;
continue;
}
if(!Character.isLetterOrDigit(s.charAt(r))) {
r--;
continue;
}
if (Character.toLowerCase(s.charAt(l)) == Character.toLowerCase(s.charAt(r))) {
l++;
r--;
} else {
return false;
}
}
return true;
}
}