Using the same value on either side of a binary operator is almost always a mistake. In the case of logical operators, it is either a copy/paste error and therefore a bug, or it is simply wasted code, and should be simplified. In the case of bitwise operators and most binary mathematical operators, having the same value on both sides of an operator yields predictable results, and should be simplified.
This rule ignores *
, +
, and =
.
if (a == b && a == b) { // Noncompliant: if the first one is true, the second one is too
doX();
}
if (a > a) { // Noncompliant: always false
doW();
}
var j = 5 / 5; //always 1
var k = 5 - 5; //always 0
The specific case of testing one variable against itself is a valid test for NaN
and is therefore ignored.
Similarly, left-shifting 1 onto 1 is common in the construction of bit masks, and is ignored.
Moreover comma operator , and instanceof
operator are ignored as there are use-cases when there usage is valid.
if (f !== f) { // test for NaN value
console.log('f is NaN');
}
var i = 1 << 1; // Compliant
var j = a << a; // Noncompliant