26.md

Results of Code LLama 34B on HumanEval/26

Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 0
Total runs: 10
Success rate: 0%

Prompt

from typing import List


def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

from typing import List


def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """import collections
    c = collections.Counter(numbers)
    return [n for n in numbers if c[n] <= 1]

Unit tests

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}


def check(candidate):
    assert candidate([]) == []
    assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
    assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]

Runs

❌ Run 1

Start time: 2023-09-01 02:48:14
Duration: 10.96s
Result: Fail

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    seen = set()
    result = []
    for num in numbers:
        if num not in seen:
            seen.add(num)
            result.append(num)
    return result

❌ Run 2

Start time: 2023-09-01 02:51:14
Duration: 5.5s
Result: Fail

from typing import List

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    return list(set(numbers))

❌ Run 3

Start time: 2023-09-01 02:54:10
Duration: 9.42s
Result: Fail

from typing import List

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    seen = set()
    result = []
    for num in numbers:
        if num not in seen:
            seen.add(num)
            result.append(num)
    return result

❌ Run 4

Start time: 2023-09-01 02:57:08
Duration: 5.26s
Result: Fail

from typing import List

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    return list(set(numbers))

❌ Run 5

Start time: 2023-09-01 03:00:06
Duration: 10.24s
Result: Fail

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    seen = set()
    result = []
    for num in numbers:
        if num not in seen:
            seen.add(num)
            result.append(num)
    return result

❌ Run 6

Start time: 2023-09-01 03:03:08
Duration: 6.05s
Result: Fail

from typing import List

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    return list(set(numbers))

❌ Run 7

Start time: 2023-09-01 03:06:11
Duration: 7.44s
Result: Fail

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    seen = set()
    result = []
    for num in numbers:
        if num not in seen:
            seen.add(num)
            result.append(num)
    return result

❌ Run 8

Start time: 2023-09-01 03:09:17
Duration: 12.66s
Result: Fail

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    seen = set()
    result = []
    for num in numbers:
        if num not in seen:
            seen.add(num)
            result.append(num)
    return result

❌ Run 9

Start time: 2023-09-01 03:12:09
Duration: 5.66s
Result: Fail

from typing import List

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    seen = set()
    return [x for x in numbers if x not in seen and not seen.add(x)]

❌ Run 10

Start time: 2023-09-01 03:15:15
Duration: 12.18s
Result: Fail

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
    seen = set()
    result = []
    for num in numbers:
        if num not in seen:
            seen.add(num)
            result.append(num)
    return result