107.md

Results of GPT-3.5 on HumanEval/107

Date: 18 July, 2023
Model: gpt-3.5-turbo
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

Tokens: 237

def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """def is_palindrome(n):
        return str(n) == str(n)[::-1]

    even_palindrome_count = 0
    odd_palindrome_count = 0

    for i in range(1, n+1):
        if i%2 == 1 and is_palindrome(i):
                odd_palindrome_count += 1
        elif i%2 == 0 and is_palindrome(i):
            even_palindrome_count += 1
    return (even_palindrome_count, odd_palindrome_count)

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate(123) == (8, 13)
    assert candidate(12) == (4, 6)
    assert candidate(3) == (1, 2)
    assert candidate(63) == (6, 8)
    assert candidate(25) == (5, 6)
    assert candidate(19) == (4, 6)
    assert candidate(9) == (4, 5), "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == (0, 1), "This prints if this assert fails 2 (also good for debugging!)"

Runs

✅ Run 1

Start time: 2023-07-18 17:11:33
Duration: 3.24s
Completion tokens: 81
Result: Pass

def even_odd_palindrome(n):
    even_count = 0
    odd_count = 0

    for num in range(1, n+1):
        if str(num) == str(num)[::-1]:
            if num % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 2

Start time: 2023-07-18 17:11:30
Duration: 3.48s
Completion tokens: 81
Result: Pass

def even_odd_palindrome(n):
    even_count = 0
    odd_count = 0

    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 3

Start time: 2023-07-18 17:11:20
Duration: 9.88s
Completion tokens: 279
Result: Pass

def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
    even_count = 0
    odd_count = 0

    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 4

Start time: 2023-07-18 17:11:10
Duration: 9.78s
Completion tokens: 279
Result: Pass

def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
    even_count = 0
    odd_count = 0

    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 5

Start time: 2023-07-18 17:11:06
Duration: 3.55s
Completion tokens: 81
Result: Pass

def even_odd_palindrome(n):
    even_count = 0
    odd_count = 0

    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 6

Start time: 2023-07-18 17:10:56
Duration: 9.8s
Completion tokens: 279
Result: Pass

def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
    even_count = 0
    odd_count = 0

    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 7

Start time: 2023-07-18 17:10:53
Duration: 3.41s
Completion tokens: 81
Result: Pass

def even_odd_palindrome(n):
    even_count = 0
    odd_count = 0
    
    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1
    
    return (even_count, odd_count)

✅ Run 8

Start time: 2023-07-18 17:10:43
Duration: 10.17s
Completion tokens: 279
Result: Pass

def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
    even_count = 0
    odd_count = 0

    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 9

Start time: 2023-07-18 17:10:32
Duration: 10.14s
Completion tokens: 279
Result: Pass

def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
    even_count = 0
    odd_count = 0

    for i in range(1, n+1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)

✅ Run 10

Start time: 2023-07-18 17:10:29
Duration: 3.66s
Completion tokens: 82
Result: Pass

def even_odd_palindrome(n):
    even_count = 0
    odd_count = 0

    for i in range(1, n + 1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even_count += 1
            else:
                odd_count += 1

    return (even_count, odd_count)