Skip to content

Latest commit

 

History

History
301 lines (299 loc) · 6.82 KB

131.md

File metadata and controls

301 lines (299 loc) · 6.82 KB

Results of GPT-4 on HumanEval/131

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

Tokens: 97

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """product = 1
    odd_count = 0
    for digit in str(n):
        int_digit = int(digit)
        if int_digit%2 == 1:
            product= product*int_digit
            odd_count+=1
    if odd_count ==0:
        return 0
    else:
        return product

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate(5) == 5
    assert candidate(54) == 5
    assert candidate(120) ==1
    assert candidate(5014) == 5
    assert candidate(98765) == 315
    assert candidate(5576543) == 2625

    # Check some edge cases that are easy to work out by hand.
    assert candidate(2468) == 0

Runs

✅ Run 1

Start time: 2023-07-18 17:58:44
Duration: 11.34s
Completion tokens: 131
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    for digit in str(n):
        if int(digit) % 2 != 0:
            product *= int(digit)
            has_odd = True
    if has_odd:
        return product
    else:
        return 0

✅ Run 2

Start time: 2023-07-18 17:58:32
Duration: 11.54s
Completion tokens: 131
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    for digit in str(n):
        if int(digit) % 2 != 0:
            product *= int(digit)
            has_odd = True
    if has_odd:
        return product
    else:
        return 0

✅ Run 3

Start time: 2023-07-18 17:58:19
Duration: 13.3s
Completion tokens: 133
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    while n > 0:
        digit = n % 10
        if digit % 2 != 0:
            product *= digit
            has_odd = True
        n //= 10
    return product if has_odd else 0

✅ Run 4

Start time: 2023-07-18 17:58:07
Duration: 11.45s
Completion tokens: 129
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    for digit in str(n):
        if int(digit) % 2 != 0:
            product *= int(digit)
            has_odd = True
    if not has_odd:
        return 0
    return product

✅ Run 5

Start time: 2023-07-18 17:57:57
Duration: 10.24s
Completion tokens: 131
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    for digit in str(n):
        if int(digit) % 2 != 0:
            product *= int(digit)
            has_odd = True
    if has_odd:
        return product
    else:
        return 0

✅ Run 6

Start time: 2023-07-18 17:57:44
Duration: 12.34s
Completion tokens: 133
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    while n > 0:
        digit = n % 10
        if digit % 2 != 0:
            product *= digit
            has_odd = True
        n //= 10
    return product if has_odd else 0

✅ Run 7

Start time: 2023-07-18 17:57:34
Duration: 10.26s
Completion tokens: 133
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    while n > 0:
        digit = n % 10
        if digit % 2 != 0:
            product *= digit
            has_odd = True
        n //= 10
    return product if has_odd else 0

✅ Run 8

Start time: 2023-07-18 17:57:21
Duration: 12.66s
Completion tokens: 133
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    while n > 0:
        digit = n % 10
        if digit % 2 != 0:
            product *= digit
            has_odd = True
        n //= 10
    return product if has_odd else 0

✅ Run 9

Start time: 2023-07-18 17:57:10
Duration: 11.57s
Completion tokens: 131
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    for digit in str(n):
        if int(digit) % 2 != 0:
            product *= int(digit)
            has_odd = True
    if has_odd:
        return product
    else:
        return 0

✅ Run 10

Start time: 2023-07-18 17:56:54
Duration: 15.27s
Completion tokens: 133
Result: Pass

def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    while n > 0:
        digit = n % 10
        if digit % 2 != 0:
            product *= digit
            has_odd = True
        n //= 10
    return product if has_odd else 0