1281-Subtract-the-Product-and-Sum-of-Digits-of-an-integer.py

'''
Given an integer number n, return the difference between the product of its digits and the sum of its digits.
 

Example 1:

Input: n = 234
Output: 15 
Explanation: 
Product of digits = 2 * 3 * 4 = 24 
Sum of digits = 2 + 3 + 4 = 9 
Result = 24 - 9 = 15
Example 2:

Input: n = 4421
Output: 21
Explanation: 
Product of digits = 4 * 4 * 2 * 1 = 32 
Sum of digits = 4 + 4 + 2 + 1 = 11 
Result = 32 - 11 = 21
 

Constraints:

1 <= n <= 10^5
'''
class Solution:
    def subtractProductAndSum(self, n: int) -> int:
        digit, s, p = 0, 0, 1
        while n > 0:
            digit = n%10
            n = n//10
            p = p * digit
            s = s + digit
        return p - s