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Make P == Q shorthand for logical biconditional instead of (P ⟹ Q) ∧ (Q ⟹ P)
P == Q
(P ⟹ Q) ∧ (Q ⟹ P)
The text was updated successfully, but these errors were encountered:
Added biconditional ⟺ and == #4
⟺
==
6af0012
How should we handle robustness and approximate robustness for vectored states?
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Added != for convenience #4
!=
b136085
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Make
P == Q
shorthand for logical biconditional instead of(P ⟹ Q) ∧ (Q ⟹ P)
The text was updated successfully, but these errors were encountered: