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etale.tex
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\input{preamble}
% OK, start here.
%
\begin{document}
\title{\'Etale Morphisms of Schemes}
\maketitle
\phantomsection
\label{section-phantom}
\tableofcontents
\section{Introduction}
\label{section-introduction}
\noindent
In this Chapter, we discuss \'etale morphisms of schemes. We illustrate
some of the more important concepts by working with the Noetherian case.
Our principal goal is to collect for the reader enough commutative
algebra results to start reading a treatise on \'etale cohomology. An
auxiliary goal is to provide enough evidence to ensure that the reader stops
calling the phrase ``the \'etale topology of schemes'' an exercise in general
nonsense, if (s)he does indulge in such blasphemy.
\medskip\noindent
We will refer to the other
chapters of the Stacks project for standard results in algebraic geometry
(on schemes and commutative algebra). We will provide detailed
proofs of the new results that we state here.
\section{Conventions}
\label{section-conventions}
\noindent
In this chapter, frequently schemes will be assumed locally Noetherian
and frequently rings will be assumed Noetherian. But in all the statements
we will reiterate this when necessary, and make sure we list all the
hypotheses! On the other hand, here are some general facts that we will use
often and are useful to keep in mind:
\begin{enumerate}
\item A ring homomorphism $A \to B$ of finite type with $A$ Noetherian
is of finite presentation. See Algebra,
Lemma \ref{algebra-lemma-Noetherian-finite-type-is-finite-presentation}.
\item A morphism (locally) of finite type between locally Noetherian schemes
is automatically (locally) of finite presentation.
See Morphisms,
Lemma \ref{morphisms-lemma-noetherian-finite-type-finite-presentation}.
\item Add more like this here.
\end{enumerate}
\section{Unramified morphisms}
\label{section-unramified-definition}
\noindent
We first define ``unramified homomorphisms of local rings'' for Noetherian
local rings. We cannot use the term ``unramified'' as there already is
a notion of
an unramified ring map (Algebra, Section \ref{algebra-section-unramified})
and it is different. After discussing the notion a bit we
globalize it to describe unramified morphisms of locally Noetherian schemes.
\begin{definition}
\label{definition-unramified-rings}
Let $A$, $B$ be Noetherian local rings. A local homomorphism $A \to B$
is said to be {\it unramified homomorphism of local rings} if
\begin{enumerate}
\item $\mathfrak m_AB = \mathfrak m_B$,
\item $\kappa(\mathfrak m_B)$ is a finite separable extension of
$\kappa(\mathfrak m_A)$, and
\item $B$ is essentially of finite type over $A$ (this means
that $B$ is the localization of a finite type $A$-algebra at a prime).
\end{enumerate}
\end{definition}
\noindent
This is the local version of the
definition in Algebra, Section \ref{algebra-section-unramified}.
In that section a ring map $R \to S$ is defined to be unramified if and
only if it is of finite type, and $\Omega_{S/R} = 0$.
We say $R \to S$ is unramified at a prime $\mathfrak q \subset S$
if there exists a $g \in S$, $g \not \in \mathfrak q$ such that
$R \to S_g$ is an unramified ring map. It is shown in
Algebra, Lemmas \ref{algebra-lemma-unramified-at-prime} and
\ref{algebra-lemma-characterize-unramified} that given a ring
map $R \to S$ of finite type, and a prime $\mathfrak q$ of $S$
lying over $\mathfrak p \subset R$, then we have
$$
R \to S\text{ is unramified at }\mathfrak q
\Leftrightarrow
\mathfrak pS_{\mathfrak q} = \mathfrak q S_{\mathfrak q}
\text{ and }
\kappa(\mathfrak p) \subset \kappa(\mathfrak q)\text{ finite separable}
$$
Thus we see that for a local homomorphism of local rings the properties
of our definition above are closely related to the question of
being unramified. In fact, we have proved the following lemma.
\begin{lemma}
\label{lemma-characterize-unramified-Noetherian}
\begin{slogan}
Unramifiedness is a stalk local condition.
\end{slogan}
Let $A \to B$ be of finite type with $A$ a Noetherian ring.
Let $\mathfrak q$ be a prime of $B$ lying over $\mathfrak p \subset A$.
Then $A \to B$ is unramified at $\mathfrak q$ if and only if
$A_{\mathfrak p} \to B_{\mathfrak q}$ is an unramified homomorphism
of local rings.
\end{lemma}
\begin{proof}
See discussion above.
\end{proof}
\noindent
We will characterize the property of being unramified in terms
of completions. For a Noetherian local ring $A$
we denote $A^\wedge$ the completion of $A$ with respect to the
maximal ideal. It is also a Noetherian local ring, see
Algebra, Lemma \ref{algebra-lemma-completion-Noetherian-Noetherian}.
\begin{lemma}
\label{lemma-unramified-completions}
Let $A$, $B$ be Noetherian local rings.
Let $A \to B$ be a local homomorphism.
\begin{enumerate}
\item if $A \to B$ is an unramified homomorphism of local rings,
then $B^\wedge$ is a finite $A^\wedge$ module,
\item if $A \to B$ is an unramified homomorphism of local rings and
$\kappa(\mathfrak m_A) = \kappa(\mathfrak m_B)$,
then $A^\wedge \to B^\wedge$ is surjective,
\item if $A \to B$ is an unramified homomorphism of local rings
and $\kappa(\mathfrak m_A)$
is separably closed, then $A^\wedge \to B^\wedge$ is surjective,
\item if $A$ and $B$ are complete discrete valuation rings, then
$A \to B$ is an unramified homomorphism of local rings
if and only if the uniformizer for $A$ maps to a uniformizer for $B$,
and the residue field extension is finite separable (and $B$ is
essentially of finite type over $A$).
\end{enumerate}
\end{lemma}
\begin{proof}
Part (1) is a special case of
Algebra, Lemma \ref{algebra-lemma-finite-after-completion}.
For part (2), note that the $\kappa(\mathfrak m_A)$-vector space
$B^\wedge/\mathfrak m_{A^\wedge}B^\wedge$
is generated by $1$. Hence by Nakayama's lemma
(Algebra, Lemma \ref{algebra-lemma-NAK}) the map
$A^\wedge \to B^\wedge$ is surjective.
Part (3) is a special case of part (2).
Part (4) is immediate from the definitions.
\end{proof}
\begin{lemma}
\label{lemma-characterize-unramified-completions}
Let $A$, $B$ be Noetherian local rings.
Let $A \to B$ be a local homomorphism such that $B$ is
essentially of finite type over $A$.
The following are equivalent
\begin{enumerate}
\item $A \to B$ is an unramified homomorphism of local rings
\item $A^\wedge \to B^\wedge$ is an unramified homomorphism of local rings, and
\item $A^\wedge \to B^\wedge$ is unramified.
\end{enumerate}
\end{lemma}
\begin{proof}
The equivalence of (1) and (2) follows from the fact that
$\mathfrak m_AA^\wedge$ is the maximal ideal of $A^\wedge$
(and similarly for $B$) and faithful flatness of $B \to B^\wedge$.
For example if $A^\wedge \to B^\wedge$ is unramified, then
$\mathfrak m_AB^\wedge = (\mathfrak m_AB)B^\wedge = \mathfrak m_BB^\wedge$
and hence $\mathfrak m_AB = \mathfrak m_B$.
\medskip\noindent
Assume the equivalent conditions (1) and (2).
By Lemma \ref{lemma-unramified-completions}
we see that $A^\wedge \to B^\wedge$ is
finite. Hence $A^\wedge \to B^\wedge$ is of finite presentation, and by
Algebra, Lemma \ref{algebra-lemma-characterize-unramified}
we conclude that $A^\wedge \to B^\wedge$ is unramified at
$\mathfrak m_{B^\wedge}$. Since $B^\wedge$ is local we conclude
that $A^\wedge \to B^\wedge$ is unramified.
\medskip\noindent
Assume (3). By Algebra, Lemma \ref{algebra-lemma-unramified-at-prime}
we conclude that $A^\wedge \to B^\wedge$ is an unramified homomorphism
of local rings, i.e., (2) holds.
\end{proof}
\begin{definition}
\label{definition-unramified-schemes}
(See Morphisms, Definition \ref{morphisms-definition-unramified}
for the definition in the general case.)
Let $Y$ be a locally Noetherian scheme.
Let $f : X \to Y$ be locally of finite type.
Let $x \in X$.
\begin{enumerate}
\item We say $f$ is {\it unramified at $x$} if
$\mathcal{O}_{Y, f(x)} \to \mathcal{O}_{X, x}$
is an unramified homomorphism of local rings.
\item The morphism $f : X \to Y$ is said to be {\it unramified}
if it is unramified at all points of $X$.
\end{enumerate}
\end{definition}
\noindent
Let us prove that this definition agrees with the definition in the
chapter on morphisms of schemes. This in particular guarantees that the
set of points where a morphism is unramified is open.
\begin{lemma}
\label{lemma-unramified-definition}
Let $Y$ be a locally Noetherian scheme.
Let $f : X \to Y$ be locally of finite type.
Let $x \in X$. The morphism $f$ is unramified at $x$ in
the sense of Definition \ref{definition-unramified-schemes}
if and only if it is unramified in
the sense of Morphisms, Definition \ref{morphisms-definition-unramified}.
\end{lemma}
\begin{proof}
This follows from Lemma \ref{lemma-characterize-unramified-Noetherian}
and the definitions.
\end{proof}
\noindent
Here are some results on unramified morphisms.
The formulations as given in this list apply only to
morphisms locally of finite type between locally Noetherian schemes.
In each case we give a reference to the general result as
proved earlier in the project, but in some cases one can
prove the result more easily in the Noetherian case.
Here is the list:
\begin{enumerate}
\item Unramifiedness is local on the source and the target in the Zariski
topology.
\item Unramified morphisms are stable under base change and composition.
See Morphisms, Lemmas \ref{morphisms-lemma-base-change-unramified}
and \ref{morphisms-lemma-composition-unramified}.
\item Unramified morphisms of schemes are locally quasi-finite
and quasi-compact unramified morphisms are quasi-finite.
See Morphisms, Lemma \ref{morphisms-lemma-unramified-quasi-finite}
\item Unramified morphisms have relative dimension $0$. See
Morphisms, Definition \ref{morphisms-definition-relative-dimension-d}
and
Morphisms, Lemma \ref{morphisms-lemma-locally-quasi-finite-rel-dimension-0}.
\item A morphism is unramified if and only if all its fibres are unramified.
That is, unramifiedness can be checked on the scheme theoretic fibres. See
Morphisms, Lemma \ref{morphisms-lemma-unramified-etale-fibres}.
\item Let $X$ and $Y$ be unramified over a base scheme $S$.
Any $S$-morphism from $X$ to $Y$ is unramified.
See Morphisms, Lemma \ref{morphisms-lemma-unramified-permanence}.
\end{enumerate}
\section{Three other characterizations of unramified morphisms}
\label{section-three-other}
\noindent
The following theorem gives three equivalent notions of being
unramified at a point. See
Morphisms, Lemma \ref{morphisms-lemma-unramified-at-point}
for (part of) the statement for general schemes.
\begin{theorem}
\label{theorem-unramified-equivalence}
Let $Y$ be a locally Noetherian scheme.
Let $f : X \to Y$ be a morphism of schemes which is locally of finite type.
Let $x$ be a point of $X$. The following are equivalent
\begin{enumerate}
\item $f$ is unramified at $x$,
\item the stalk $\Omega_{X/Y, x}$ of the module of relative differentials
at $x$ is trivial,
\item there exist open neighbourhoods $U$ of $x$ and $V$ of $f(x)$, and a
commutative diagram
$$
\xymatrix{
U \ar[rr]_i \ar[rd] & & \mathbf{A}^n_V \ar[ld] \\
& V
}
$$
where $i$ is a closed immersion defined by a
quasi-coherent sheaf of ideals $\mathcal{I}$ such that the differentials
$\text{d}g$ for $g \in \mathcal{I}_{i(x)}$ generate
$\Omega_{\mathbf{A}^n_V/V, i(x)}$, and
\item the diagonal $\Delta_{X/Y} : X \to X \times_Y X$
is a local isomorphism at $x$.
\end{enumerate}
\end{theorem}
\begin{proof}
The equivalence of (1) and (2) is proved in
Morphisms, Lemma \ref{morphisms-lemma-unramified-at-point}.
\medskip\noindent
If $f$ is unramified at $x$, then $f$ is unramified in an open
neighbourhood of $x$; this does not follow immediately
from Definition \ref{definition-unramified-schemes} of this chapter
but it does follow from
Morphisms, Definition \ref{morphisms-definition-unramified} which we
proved to be equivalent in
Lemma \ref{lemma-unramified-definition}.
Choose affine opens $V \subset Y$, $U \subset X$
with $f(U) \subset V$ and $x \in U$, such that $f$ is
unramified on $U$, i.e., $f|_U : U \to V$ is unramified.
By Morphisms, Lemma \ref{morphisms-lemma-diagonal-unramified-morphism}
the morphism $U \to U \times_V U$
is an open immersion. This proves that (1) implies (4).
\medskip\noindent
If $\Delta_{X/Y}$ is a local isomorphism at $x$, then
$\Omega_{X/Y, x} = 0$ by
Morphisms, Lemma \ref{morphisms-lemma-differentials-diagonal}.
Hence we see that (4) implies (2).
At this point we know that (1), (2) and (4) are all equivalent.
\medskip\noindent
Assume (3). The assumption on the diagram combined with
Morphisms, Lemma \ref{morphisms-lemma-differentials-relative-immersion}
show that $\Omega_{U/V, x} = 0$. Since $\Omega_{U/V, x} = \Omega_{X/Y, x}$
we conclude (2) holds.
\medskip\noindent
Finally, assume that (2) holds. To prove (3) we may localize on
$X$ and $Y$ and assume that $X$ and $Y$ are affine.
Say $X = \Spec(B)$ and $Y = \Spec(A)$.
The point $x \in X$ corresponds to a prime $\mathfrak q \subset B$.
Our assumption is that $\Omega_{B/A, \mathfrak q} = 0$
(see Morphisms, Lemma \ref{morphisms-lemma-differentials-affine} for the
relationship between differentials on schemes and modules
of differentials in commutative algebra).
Since $Y$ is locally Noetherian and $f$ locally of finite type
we see that $A$ is Noetherian and
$B \cong A[x_1, \ldots, x_n]/(f_1, \ldots, f_m)$, see
Properties, Lemma \ref{properties-lemma-locally-Noetherian} and
Morphisms, Lemma \ref{morphisms-lemma-locally-finite-type-characterize}.
In particular, $\Omega_{B/A}$ is a finite $B$-module. Hence we
can find a single $g \in B$, $g \not \in \mathfrak q$ such that
the principal localization $(\Omega_{B/A})_g$ is zero. Hence after
replacing $B$ by $B_g$ we see that $\Omega_{B/A} = 0$ (formation
of modules of differentials commutes with localization, see
Algebra, Lemma \ref{algebra-lemma-differentials-localize}). This means that
$\text{d}(f_j)$ generate the kernel of the canonical map
$\Omega_{A[x_1, \ldots, x_n]/A} \otimes_A B \to \Omega_{B/A}$.
Thus the surjection $A[x_1, \ldots, x_n] \to B$ of $A$-algebras gives the
commutative diagram of (3), and the theorem is proved.
\end{proof}
\noindent
How can we use this theorem? Well, here are a few remarks:
\begin{enumerate}
\item Suppose that
$f : X \to Y$ and $g : Y \to Z$ are two morphisms locally of finite
type between locally Noetherian schemes. There is a canonical short
exact sequence
$$
f^*(\Omega_{Y/Z}) \to \Omega_{X/Z} \to \Omega_{X/Y} \to 0
$$
see Morphisms, Lemma \ref{morphisms-lemma-triangle-differentials}.
The theorem therefore implies that if $g \circ f$ is unramified,
then so is $f$. This is
Morphisms, Lemma \ref{morphisms-lemma-unramified-permanence}.
\item Since $\Omega_{X/Y}$ is isomorphic to the conormal sheaf
of the diagonal morphism
(Morphisms, Lemma \ref{morphisms-lemma-differentials-diagonal})
we see that if $X \to Y$ is a monomorphism of
locally Noetherian schemes and locally of finite type,
then $X \to Y$ is unramified.
In particular, open and closed immersions of locally Noetherian schemes
are unramified. See
Morphisms, Lemmas
\ref{morphisms-lemma-open-immersion-unramified} and
\ref{morphisms-lemma-closed-immersion-unramified}.
\item The theorem also implies that the set of points
where a morphism $f : X \to Y$ (locally of finite type of locally Noetherian
schemes) is not unramified is
the support of the coherent sheaf $\Omega_{X/Y}$.
This allows one to give a scheme theoretic definition to the
``ramification locus''.
\end{enumerate}
\section{The functorial characterization of unramified morphisms}
\label{section-functorial-unramified}
\noindent
In basic algebraic geometry we learn that some classes of morphisms can be
characterized functorially, and that such descriptions are quite useful.
Unramified morphisms too have such a characterization.
\begin{theorem}
\label{theorem-formally-unramified}
Let $f : X \to S$ be a morphism of schemes.
Assume $S$ is a locally Noetherian scheme, and $f$ is locally of finite type.
Then the following are equivalent:
\begin{enumerate}
\item $f$ is unramified,
\item the morphism $f$ is formally unramified:
for any affine $S$-scheme $T$ and subscheme $T_0$ of $T$
defined by a square-zero ideal,
the natural map
$$
\Hom_S(T, X) \longrightarrow \Hom_S(T_0, X)
$$
is injective.
\end{enumerate}
\end{theorem}
\begin{proof}
See More on Morphisms,
Lemma \ref{more-morphisms-lemma-unramified-formally-unramified}
for a more general statement and proof.
What follows is a sketch of the proof in the current case.
\medskip\noindent
Firstly, one checks both properties are local on the source and the target.
This we may assume that $S$ and $X$ are affine.
Say $X = \Spec(B)$ and $S = \Spec(R)$.
Say $T = \Spec(C)$. Let $J$ be the square-zero ideal of $C$
with $T_0 = \Spec(C/J)$. Assume that we are given the diagram
$$
\xymatrix{
& B \ar[d]^\phi \ar[rd]^{\bar{\phi}}
& \\
R \ar[r] \ar[ur] & C \ar[r]
& C/J
}
$$
Secondly, one checks that the association $\phi' \mapsto \phi' - \phi$
gives a bijection between the set of liftings of $\bar{\phi}$ and the module
$\text{Der}_R(B, J)$. Thus, we obtain the implication (1) $\Rightarrow$ (2)
via the description of unramified morphisms having trivial module
of differentials, see Theorem \ref{theorem-unramified-equivalence}.
\medskip\noindent
To obtain the reverse implication, consider the surjection
$q : C = (B \otimes_R B)/I^2 \to B = C/J$ defined by the square zero ideal
$J = I/I^2$ where $I$ is the kernel of the multiplication map
$B \otimes_R B \to B$. We already have a lifting $B \to C$ defined by, say,
$b \mapsto b \otimes 1$. Thus, by the same reasoning as above, we obtain a
bijective correspondence between liftings of $\text{id} : B \to C/J$ and
$\text{Der}_R(B, J)$. The hypothesis therefore implies that the latter module is
trivial. But we know that $J \cong \Omega_{B/R}$. Thus, $B/R$ is unramified.
\end{proof}
\section{Topological properties of unramified morphisms}
\label{section-topological-unramified}
\noindent
The first topological result that will be of utility to us is one which says
that unramified and separated morphisms have ``nice'' sections.
The material in this section does not require any Noetherian hypotheses.
\begin{proposition}
\label{proposition-properties-sections}
Sections of unramified morphisms.
\begin{enumerate}
\item Any section of an unramified morphism is an open immersion.
\item Any section of a separated morphism is a closed immersion.
\item Any section of an unramified separated morphism is open and closed.
\end{enumerate}
\end{proposition}
\begin{proof}
Fix a base scheme $S$.
If $f : X' \to X$ is any $S$-morphism, then the graph
$\Gamma_f : X' \to X' \times_S X$
is obtained as the base change of the diagonal
$\Delta_{X/S} : X \to X \times_S X$ via the projection
$X' \times_S X \to X \times_S X$.
If $g : X \to S$ is separated (resp. unramified)
then the diagonal is a closed immersion (resp. open immersion)
by Schemes, Definition \ref{schemes-definition-separated}
(resp.\ Morphisms, Lemma \ref{morphisms-lemma-diagonal-unramified-morphism}).
Hence so is the graph as a base change (by
Schemes, Lemma \ref{schemes-lemma-base-change-immersion}).
In the special case $X' = S$, we obtain (1), resp.\ (2).
Part (3) follows on combining (1) and (2).
\end{proof}
\noindent
We can now explicitly describe the sections of unramified morphisms.
\begin{theorem}
\label{theorem-sections-unramified-maps}
Let $Y$ be a connected scheme.
Let $f : X \to Y$ be unramified and separated.
Every section of $f$ is an isomorphism onto a connected component.
There exists a bijective correspondence
$$
\text{sections of }f
\leftrightarrow
\left\{
\begin{matrix}
\text{connected components }X'\text{ of }X\text{ such that}\\
\text{the induced map }X' \to Y\text{ is an isomorphism}
\end{matrix}
\right\}
$$
In particular, given $x \in X$ there is at most one
section passing through $x$.
\end{theorem}
\begin{proof}
Direct from Proposition \ref{proposition-properties-sections} part (3).
\end{proof}
\noindent
The preceding theorem gives us some idea of the ``rigidity'' of unramified
morphisms. Further indication is provided by the following proposition
which, besides being intrinsically interesting, is also useful in the
theory of the algebraic fundamental group (see \cite[Expos\'e V]{SGA1}).
See also the more general
Morphisms, Lemma \ref{morphisms-lemma-value-at-one-point}.
\begin{proposition}
\label{proposition-equality}
Let $S$ is be a scheme.
Let $\pi : X \to S$ be unramified and separated.
Let $Y$ be an $S$-scheme and $y \in Y$ a point.
Let $f, g : Y \to X$ be two $S$-morphisms. Assume
\begin{enumerate}
\item $Y$ is connected
\item $x = f(y) = g(y)$, and
\item the induced maps $f^\sharp, g^\sharp : \kappa(x) \to \kappa(y)$
on residue fields are equal.
\end{enumerate}
Then $f = g$.
\end{proposition}
\begin{proof}
The maps $f, g : Y \to X$ define maps $f', g' : Y \to X_Y = Y \times_S X$
which are sections of the structure map $X_Y \to Y$.
Note that $f = g$ if and only if $f' = g'$.
The structure map $X_Y \to Y$ is the base change of $\pi$ and hence
unramified and separated also (see
Morphisms, Lemmas \ref{morphisms-lemma-base-change-unramified} and
Schemes, Lemma \ref{schemes-lemma-separated-permanence}).
Thus according to Theorem \ref{theorem-sections-unramified-maps}
it suffices to prove that $f'$ and $g'$ pass through the same
point of $X_Y$. And this is exactly what the hypotheses (2) and (3)
guarantee, namely $f'(y) = g'(y) \in X_Y$.
\end{proof}
\begin{lemma}
\label{lemma-finitely-many-maps-to-unramified}
Let $S$ be a Noetherian scheme. Let $X \to S$ be a quasi-compact unramified
morphism. Let $Y \to S$ be a morphism with $Y$ Noetherian. Then
$\Mor_S(Y, X)$ is a finite set.
\end{lemma}
\begin{proof}
Assume first $X \to S$ is separated (which is often the case in practice).
Since $Y$ is Noetherian it has finitely many connected components. Thus we
may assume $Y$ is connected. Choose a point $y \in Y$ with image $s \in S$.
Since $X \to S$ is unramified and quasi-compact
then fibre $X_s$ is finite, say $X_s = \{x_1, \ldots, x_n\}$
and $\kappa(x_i)/\kappa(s)$ is a finite field extension.
See Morphisms, Lemma \ref{morphisms-lemma-unramified-quasi-finite},
\ref{morphisms-lemma-residue-field-quasi-finite}, and
\ref{morphisms-lemma-quasi-finite}.
For each $i$ there are at most finitely many $\kappa(s)$-algebra
maps $\kappa(x_i) \to \kappa(y)$ (by elementary field theory).
Thus $\Mor_S(Y, X)$ is finite by
Proposition \ref{proposition-equality}.
\medskip\noindent
General case. There exists a nonempty open $U \subset S$ such
that $X_U \to U$ is finite (in particular separated), see
Morphisms, Lemma \ref{morphisms-lemma-generically-finite}
(the lemma applies since we've already seen above that a quasi-compact
unramified morphism is quasi-finite and since $X \to S$ is quasi-separated by
Morphisms, Lemma \ref{morphisms-lemma-finite-type-Noetherian-quasi-separated}).
Let $Z \subset S$ be the reduced closed subscheme supported on
the complement of $U$. By Noetherian induction, we see that
$\Mor_Z(Y_Z, X_Z)$ is finite (details omitted).
By the result of the first paragraph the set
$\Mor_U(Y_U, X_U)$ is finite. Thus it suffices to show that
$$
\Mor_S(Y, X) \longrightarrow \Mor_Z(Y_Z, X_Z) \times \Mor_U(Y_U, X_U)
$$
is injective. This follows from the fact that the set of points where
two morphisms $a, b : Y \to X$ agree is open in $Y$, due to the fact
that $\Delta : X \to X \times_S X$ is open, see
Morphisms, Lemma \ref{morphisms-lemma-diagonal-unramified-morphism}.
\end{proof}
\section{Universally injective, unramified morphisms}
\label{section-universally-injective-unramified}
\noindent
Recall that a morphism of schemes $f : X \to Y$ is universally
injective if any base change of $f$ is injective (on underlying
topological spaces), see
Morphisms, Definition \ref{morphisms-definition-universally-injective}.
Universally injective and unramified morphisms can be
characterized as follows.
\begin{lemma}
\label{lemma-universally-injective-unramified}
Let $f : X \to S$ be a morphism of schemes.
The following are equivalent:
\begin{enumerate}
\item $f$ is unramified and a monomorphism,
\item $f$ is unramified and universally injective,
\item $f$ is locally of finite type and a monomorphism,
\item $f$ is universally injective, locally of finite type, and
formally unramified,
\item $f$ is locally of finite type and $X_s$ is either empty
or $X_s \to s$ is an isomorphism for all $s \in S$.
\end{enumerate}
\end{lemma}
\begin{proof}
We have seen in
More on Morphisms, Lemma
\ref{more-morphisms-lemma-unramified-formally-unramified}
that being formally unramified and locally of finite type is the same thing
as being unramified. Hence (4) is equivalent to (2).
A monomorphism is certainly universally injective and
formally unramified hence (3) implies (4).
It is clear that (1) implies (3). Finally, if (2) holds, then
$\Delta : X \to X \times_S X$ is both an open immersion
(Morphisms, Lemma \ref{morphisms-lemma-diagonal-unramified-morphism})
and surjective
(Morphisms, Lemma \ref{morphisms-lemma-universally-injective})
hence an isomorphism, i.e., $f$ is a monomorphism. In this way we see that
(2) implies (1).
\medskip\noindent
Condition (3) implies (5) because monomorphisms are preserved under
base change
(Schemes, Lemma \ref{schemes-lemma-base-change-monomorphism})
and because of the description of monomorphisms towards the spectra of fields
in
Schemes, Lemma \ref{schemes-lemma-mono-towards-spec-field}.
Condition (5) implies (4) by
Morphisms, Lemmas \ref{morphisms-lemma-universally-injective} and
\ref{morphisms-lemma-unramified-etale-fibres}.
\end{proof}
\noindent
This leads to the following useful characterization of closed immersions.
\begin{lemma}
\label{lemma-characterize-closed-immersion}
Let $f : X \to S$ be a morphism of schemes.
The following are equivalent:
\begin{enumerate}
\item $f$ is a closed immersion,
\item $f$ is a proper monomorphism,
\item $f$ is proper, unramified, and universally injective,
\item $f$ is universally closed, unramified, and a monomorphism,
\item $f$ is universally closed, unramified, and universally injective,
\item $f$ is universally closed, locally of finite type, and a monomorphism,
\item $f$ is universally closed, universally injective, locally of
finite type, and formally unramified.
\end{enumerate}
\end{lemma}
\begin{proof}
The equivalence of (4) -- (7) follows immediately from
Lemma \ref{lemma-universally-injective-unramified}.
\medskip\noindent
Let $f : X \to S$ satisfy (6). Then $f$ is separated, see
Schemes, Lemma \ref{schemes-lemma-monomorphism-separated}
and has finite fibres. Hence
More on Morphisms, Lemma \ref{more-morphisms-lemma-characterize-finite}
shows $f$ is finite. Then
Morphisms, Lemma \ref{morphisms-lemma-finite-monomorphism-closed}
implies $f$ is a closed immersion, i.e., (1) holds.
\medskip\noindent
Note that (1) $\Rightarrow$ (2) because a closed immersion is
proper and a monomorphism
(Morphisms, Lemma \ref{morphisms-lemma-closed-immersion-proper}
and
Schemes, Lemma \ref{schemes-lemma-immersions-monomorphisms}).
By
Lemma \ref{lemma-universally-injective-unramified}
we see that (2) implies (3). It is clear that (3) implies (5).
\end{proof}
\noindent
Here is another result of a similar flavor.
\begin{lemma}
\label{lemma-finite-unramified-one-point}
Let $\pi : X \to S$ be a morphism of schemes. Let $s \in S$.
Assume that
\begin{enumerate}
\item $\pi$ is finite,
\item $\pi$ is unramified,
\item $\pi^{-1}(\{s\}) = \{x\}$, and
\item $\kappa(s) \subset \kappa(x)$ is purely
inseparable\footnote{In view of condition (2)
this is equivalent to $\kappa(s) = \kappa(x)$.}.
\end{enumerate}
Then there exists an open neighbourhood $U$ of $s$ such that
$\pi|_{\pi^{-1}(U)} : \pi^{-1}(U) \to U$ is a closed immersion.
\end{lemma}
\begin{proof}
The question is local on $S$. Hence we may assume that $S = \Spec(A)$.
By definition of a finite morphism this implies $X = \Spec(B)$.
Note that the ring map $\varphi : A \to B$ defining $\pi$
is a finite unramified ring map.
Let $\mathfrak p \subset A$ be the prime corresponding to $s$.
Let $\mathfrak q \subset B$ be the prime corresponding to $x$.
Conditions (2), (3) and (4) imply that
$B_{\mathfrak q}/\mathfrak pB_{\mathfrak q} = \kappa(\mathfrak p)$.
By Algebra, Lemma \ref{algebra-lemma-unique-prime-over-localize-below}
we have $B_{\mathfrak q} = B_{\mathfrak p}$
(note that a finite ring map satisfies going up, see
Algebra, Section \ref{algebra-section-going-up}.)
Hence we see that
$B_{\mathfrak p}/\mathfrak pB_{\mathfrak p} = \kappa(\mathfrak p)$.
As $B$ is a finite $A$-module we see from Nakayama's lemma (see
Algebra, Lemma \ref{algebra-lemma-NAK})
that $B_{\mathfrak p} = \varphi(A_{\mathfrak p})$. Hence (using the finiteness
of $B$ as an $A$-module again) there exists a
$f \in A$, $f \not \in \mathfrak p$ such that $B_f = \varphi(A_f)$
as desired.
\end{proof}
\noindent
The topological results presented above will be used to give a functorial
characterization of \'etale morphisms similar to Theorem
\ref{theorem-formally-unramified}.
\section{Examples of unramified morphisms}
\label{section-examples}
\noindent
Here are a few examples.
\begin{example}
\label{example-etale-field-extensions}
Let $k$ be a field.
Unramified quasi-compact morphisms $X \to \Spec(k)$ are affine.
This is true because $X$ has dimension $0$ and is Noetherian,
hence is a finite discrete set, and each point gives an affine open,
so $X$ is a finite disjoint union of affines hence affine.
Noether normalization forces $X$ to be the spectrum of a finite
$k$-algebra $A$.
This algebra is a product of finite separable field extensions of $k$.
Thus, an unramified quasi-compact morphism to $\Spec(k)$
corresponds to a finite number of finite separable field extensions of $k$.
In particular, an unramified morphism with a connected source and a one point
target is forced to be a finite separable field extension.
As we will see later, $X \to \Spec(k)$ is \'etale if and
only if it is unramified. Thus, in this case at least, we obtain a very easy
description of the \'etale topology of a scheme. Of course, the cohomology of
this topology is another story.
\end{example}
\begin{example}
\label{example-standard-etale}
Property (3) in
Theorem \ref{theorem-unramified-equivalence}
gives us a canonical source of examples for unramified morphisms.
Fix a ring $R$ and an integer $n$. Let $I = (g_1, \ldots, g_m)$ be an
ideal in $R[x_1, \ldots, x_n]$. Let $\mathfrak q \subset R[x_1, \ldots, x_n]$
be a prime. Assume $I \subset \mathfrak q$ and that the matrix
$$
\left(\frac{\partial g_i}{\partial x_j}\right) \bmod \mathfrak q
\quad\in\quad
\text{Mat}(n \times m, \kappa(\mathfrak q))
$$
has rank $n$. Then the morphism
$f : Z = \Spec(R[x_1, \ldots, x_n]/I) \to \Spec(R)$
is unramified at the point $x \in Z \subset \mathbf{A}^n_R$ corresponding
to $\mathfrak q$. Clearly we must have $m \geq n$.
In the extreme case $m = n$, i.e., the differential of the map
$\mathbf{A}^n_R \to \mathbf{A}^n_R$ defined by the $g_i$'s
is an isomorphism of the tangent spaces, then $f$ is also flat
$x$ and, hence, is an \'etale map (see Algebra,
Definition \ref{algebra-definition-standard-smooth},
Lemma \ref{algebra-lemma-standard-smooth} and
Example \ref{algebra-example-make-standard-smooth}).
\end{example}
\begin{example}
\label{example-number-theory-etale}
Fix an extension of number fields $L/K$ with rings of integers
$\mathcal{O}_L$ and $\mathcal{O}_K$. The injection $K \to L$ defines a
morphism $f : \Spec(\mathcal{O}_L) \to \Spec(\mathcal{O}_K)$.
As discussed above, the points where $f$ is unramified in our sense
correspond to the set of points where $f$ is unramified in the conventional
sense. In the conventional sense, the locus of ramification in
$\Spec(\mathcal{O}_L)$ can be defined by vanishing set of the
different; this is an ideal in $\mathcal{O}_L$. In fact, the different is
nothing but the annihilator of the module
$\Omega_{\mathcal{O}_L/\mathcal{O}_K}$. Similarly, the
discriminant is an ideal in $\mathcal{O}_K$, namely it is the
norm of the different.
The vanishing set of the discriminant is precisely the set
of points of $K$ which ramify in $L$.
Thus, denoting by $X$ the complement of the closed subset
defined by the different in $\Spec(\mathcal{O}_L)$,
we obtain a morphism $X \to \Spec(\mathcal{O}_K)$ which is unramified.
Furthermore, this morphism is also flat, as any local homomorphism
of discrete valuation rings is flat, and hence this morphism is
actually \'etale. If $L/K$ is finite Galois, then denoting by
$Y$ the complement of the closed subset defined by the discriminant in
$\Spec(\mathcal{O}_K)$, we see that we get even a
finite \'etale morphism $X \to Y$.
Thus, this is an example of a finite \'etale covering.
\end{example}
\section{Flat morphisms}
\label{section-flat-morphisms}
\noindent
This section simply exists to summarize the properties of flatness that will
be useful to us. Thus, we will be content with stating the theorems precisely
and giving references for the proofs.
\medskip\noindent
After briefly recalling the necessary facts about flat modules over Noetherian
rings, we state a theorem of Grothendieck which gives sufficient conditions
for ``hyperplane sections'' of certain modules to be flat.
\begin{definition}
\label{definition-flat-rings}
Flatness of modules and rings.
\begin{enumerate}
\item A module $N$ over a ring $A$ is said to be {\it flat}
if the functor $M \mapsto M \otimes_A N$ is exact.
\item If this functor is also faithful, we say that
$N$ is {\it faithfully flat} over $A$.
\item A morphism of rings $f : A \to B$ is said to be
{\it flat (resp. faithfully flat)}
if the functor $M \mapsto M \otimes_A B$ is exact
(resp. faithful and exact).
\end{enumerate}
\end{definition}
\noindent
Here is a list of facts with references to the algebra chapter.
\begin{enumerate}
\item Free and projective modules are flat. This is clear for free modules
and follows for projective modules as they are direct summands of free
modules and $\otimes$ commutes with direct sums.
\item Flatness is a local property, that is, $M$ is flat over $A$
if and only if $M_{\mathfrak p}$ is flat over $A_{\mathfrak p}$ for all
$\mathfrak p \in \Spec(A)$.
See Algebra, Lemma \ref{algebra-lemma-flat-localization}.
\item If $M$ is a flat $A$-module and $A \to B$ is a ring map,
then $M \otimes_A B$ is a flat $B$-module. See
Algebra, Lemma \ref{algebra-lemma-flat-base-change}.
\item Finite flat modules over local rings are free.
See Algebra, Lemma \ref{algebra-lemma-finite-flat-local}.
\item If $f : A \to B$ is a morphism of arbitrary rings,
$f$ is flat if and only if the induced maps
$A_{f^{-1}(\mathfrak q)} \to B_{\mathfrak q}$ are flat for all
$\mathfrak q \in \Spec(B)$.
See Algebra, Lemma \ref{algebra-lemma-flat-localization}
\item If $f : A \to B$ is a local homomorphism of local rings,
$f$ is flat if and only if it is faithfully flat.
See Algebra, Lemma \ref{algebra-lemma-local-flat-ff}.
\item A map $A \to B$ of rings is faithfully flat if and only if it is
flat and the induced map on spectra is surjective.
See Algebra, Lemma \ref{algebra-lemma-ff-rings}.
\item If $A$ is a Noetherian local ring, the completion
$A^\wedge$ is faithfully flat over $A$.
See Algebra, Lemma \ref{algebra-lemma-completion-faithfully-flat}.
\item Let $A$ be a Noetherian local ring and $M$ an $A$-module.
Then $M$ is flat over $A$ if and only if $M \otimes_A A^\wedge$
is flat over $A^\wedge$. (Combine the previous statement with
Algebra, Lemma \ref{algebra-lemma-flatness-descends}.)
\end{enumerate}
Before we move on to the geometric category, we present Grothendieck's
theorem, which provides a convenient recipe for producing flat
modules.
\begin{theorem}
\label{theorem-flatness-grothendieck}
Let $A$, $B$ be Noetherian local rings.
Let $f : A \to B$ be a local homomorphism.
If $M$ is a finite $B$-module that is flat as an $A$-module,
and $t \in \mathfrak m_B$ is an element such that multiplication
by $t$ is injective on $M/\mathfrak m_AM$, then $M/tM$ is also $A$-flat.
\end{theorem}
\begin{proof}
See Algebra, Lemma \ref{algebra-lemma-mod-injective}.
See also \cite[Section 20]{MatCA}.
\end{proof}
\begin{definition}
\label{definition-flat-schemes}
(See Morphisms, Definition \ref{morphisms-definition-flat}).
Let $f : X \to Y$ be a morphism of schemes.
Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module.
\begin{enumerate}
\item Let $x \in X$. We say $\mathcal{F}$ is
{\it flat over $Y$ at $x \in X$} if $\mathcal{F}_x$
is a flat $\mathcal{O}_{Y, f(x)}$-module.
This uses the map $\mathcal{O}_{Y, f(x)} \to \mathcal{O}_{X, x}$ to
think of $\mathcal{F}_x$ as a $\mathcal{O}_{Y, f(x)}$-module.
\item Let $x \in X$. We say $f$ is {\it flat at $x \in X$}
if $\mathcal{O}_{Y, f(x)} \to \mathcal{O}_{X, x}$ is flat.
\item We say $f$ is {\it flat} if it is flat at all points of $X$.
\item A morphism $f : X \to Y$ that is flat and surjective is sometimes
said to be {\it faithfully flat}.
\end{enumerate}
\end{definition}
\noindent
Once again, here is a list of results:
\begin{enumerate}
\item The property (of a morphism) of being flat is, by fiat,
local in the Zariski topology on the source and the target.
\item Open immersions are flat. (This is clear because it induces isomorphisms
on local rings.)
\item Flat morphisms are stable under base change and composition.
Morphisms, Lemmas \ref{morphisms-lemma-base-change-flat} and
\ref{morphisms-lemma-composition-flat}.
\item If $f : X \to Y$ is flat, then the pullback functor
$\QCoh(\mathcal{O}_Y) \to \QCoh(\mathcal{O}_X)$ is exact.
This is immediate by looking at stalks.
\item Let $f : X \to Y$ be a morphism of schemes, and assume $Y$
is quasi-compact and quasi-separated. In this case
if the functor $f^*$ is exact then $f$ is flat.
(Proof omitted. Hint: Use
Properties, Lemma \ref{properties-lemma-extend-trivial} to see that
$Y$ has ``enough'' ideal sheaves and use the characterization of
flatness in Algebra, Lemma \ref{algebra-lemma-flat}.)
\end{enumerate}
\section{Topological properties of flat morphisms}
\label{section-topological-flat}
\noindent
We ``recall'' below some openness properties that flat morphisms enjoy.
\begin{theorem}
\label{theorem-flat-open}
Let $Y$ be a locally Noetherian scheme.
Let $f : X \to Y$ be a morphism which is locally of finite type.
Let $\mathcal{F}$ be a coherent $\mathcal{O}_X$-module.
The set of points in $X$ where $\mathcal{F}$ is flat over $Y$ is an open set.
In particular the set of points where $f$ is flat is open in $X$.
\end{theorem}
\begin{proof}
See More on Morphisms, Theorem \ref{more-morphisms-theorem-openness-flatness}.
\end{proof}
\begin{theorem}
\label{theorem-flat-map-open}
Let $Y$ be a locally Noetherian scheme.
Let $f : X \to Y$ be a morphism which is flat and locally of finite type.
Then $f$ is (universally) open.
\end{theorem}
\begin{proof}
See Morphisms, Lemma \ref{morphisms-lemma-fppf-open}.
\end{proof}
\begin{theorem}
\label{theorem-flat-is-quotient}
A faithfully flat quasi-compact morphism is a quotient map for
the Zariski topology.
\end{theorem}
\begin{proof}
See Morphisms, Lemma \ref{morphisms-lemma-fpqc-quotient-topology}.
\end{proof}
\noindent