StopIteration Error for IO_in1

[drmingle]

I tried to run this code and received a StopIteration error.

# IO_in1.txt
import sys
inputs = iter(sys.stdin.readlines())
TC = int(next(inputs))
for _ in range(TC):
    print(sum(map(int, next(inputs).split())))

Can you tell me how to prevent this traceback?

---------------------------------------------------------------------------
StopIteration                             Traceback (most recent call last)
<ipython-input-221-4615b4523133> in <module>
      1 import sys
      2 inputs = iter(sys.stdin.readlines())
----> 3 TC = int(next(inputs))
      4 for _ in range(TC):
      5     print(sum(map(int, next(inputs).split())))

StopIteration: 

[stevenhalim]

Hi Damian, When you feed input to the Python interpreter, use the EOF symbol CTRL+D (on Windows) or CTRL+Z? (on Linux/Mac - I am not sure) after the last line of input. Because inputs = iter(sys.stdin.readlines()) reads all input at one go. Alternatively, use command line IO redirection like this

> python IO.py < IO_in1.txt

Regards, Steven Halim (Dr.) Senior Lecturer School of Computing, National University of Singapore <http://www.comp.nus.edu.sg/~stevenha> IOI 2020 (https://ioi2020.sg/) and 2021 (http://ioi2021.sg/) Deputy Director+IC Member https://visualgo.net and https://cpbook.net (CP4 is out)

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On Tue, Dec 29, 2020 at 1:04 PM Damian Mingle ***@***.***> wrote: I tried to run this code and received a StopIteration error. # IO_in1.txt import sys inputs = iter(sys.stdin.readlines()) TC = int(next(inputs)) for _ in range(TC): print(sum(map(int, next(inputs).split()))) Can you tell me how to prevent this traceback? --------------------------------------------------------------------------- StopIteration Traceback (most recent call last) <ipython-input-221-4615b4523133> in <module> 1 import sys 2 inputs = iter(sys.stdin.readlines()) ----> 3 TC = int(next(inputs)) 4 for _ in range(TC): 5 print(sum(map(int, next(inputs).split()))) StopIteration: — You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHub <#83>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/ABIDWOEP4P6HQYNJCS22LE3SXFPMTANCNFSM4VMZSJPA> .