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name不是数据对象的唯一标识问题 #2003
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你可以通过object id拿到之前的数据,如果必须要用name对应一个object的时候,需要确保name不会被覆盖。另外你预期覆盖后是个什么行为比较好呢? |
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@Daniel-blue Thanks for the detail. We can validate whether the name exists and make sure the object-name mapping not to be overwritten. |
/cc @sighingnow, this issus/pr has had no activity for a long time, please help to review the status and assign people to work on it. |
以name作为数据对象的唯一标识来存取数据,这种场景用户理解name是唯一标识,只存一份数据。但是当前以同一个name put两份数据,两份数据都会存进vineyard数据库里,元数据里的name是一样的;通过name取的是最新的一份数据,请问vineyard的设计是如何考虑的?老的数据是不是相当于残留了?
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