L27Q5_DateConverter.py

# Question 5: Date Converter

# Write a procedure date_converter which takes two inputs. The first is
# a dictionary and the second a string. The string is a valid date in
# the format month/day/year. The procedure should return
# the date written in the form <day> <name of month> <year>.
# For example , if the
# dictionary is in English,

english = {1:"January", 2:"February", 3:"March", 4:"April", 5:"May",
6:"June", 7:"July", 8:"August", 9:"September",10:"October",
11:"November", 12:"December"}

# then  "5/11/2012" should be converted to "11 May 2012".
# If the dictionary is in Swedish

swedish = {1:"januari", 2:"februari", 3:"mars", 4:"april", 5:"maj",
6:"juni", 7:"juli", 8:"augusti", 9:"september",10:"oktober",
11:"november", 12:"december"}

# then "5/11/2012" should be converted to "11 maj 2012".
# Hint: int('12') converts the string '12' to the integer 12

#my solution
def date_converter(zone,date):
    begin = date.find('/')+1
    end = date.find('/',date.find('/')+1)
    day = date[begin:end]
    month = date[:begin-1]
    year = date[end+1:]
    return day + ' ' + zone.get(int(month)) + ' ' + year

#udacity solution
def date_converterUdacity(zone,date):
    day,month,year = date.split('/')
    return day + ' ' + zone.get(int(month)) + ' ' + year

print date_converterUdacity(english, '5/11/2012')
#>>> 11 May 2012

print date_converter(english, '5/11/12')
#>>> 11 May 12

print date_converter(swedish, '5/11/2012')
#>>> 11 maj 2012

print date_converter(swedish, '12/5/1791')
#>>> 5 december 1791