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题目描述

表: Warehouse

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| name         | varchar |
| product_id   | int     |
| units        | int     |
+--------------+---------+
(name, product_id) 是该表主键.
该表的行包含了每个仓库的所有商品信息.

 

表: Products

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| product_id    | int     |
| product_name  | varchar |
| Width         | int     |
| Length        | int     |
| Height        | int     |
+---------------+---------+
product_id 是该表主键.
该表的行包含了每件商品以英尺为单位的尺寸(宽度, 长度和高度)信息.

 

写一个 SQL 查询来报告, 每个仓库的存货量是多少立方英尺.

  • 仓库名
  • 存货量

返回结果没有顺序要求.

查询结果如下例所示.

 

Warehouse 表:
+------------+--------------+-------------+
| name       | product_id   | units       |
+------------+--------------+-------------+
| LCHouse1   | 1            | 1           |
| LCHouse1   | 2            | 10          |
| LCHouse1   | 3            | 5           |
| LCHouse2   | 1            | 2           |
| LCHouse2   | 2            | 2           |
| LCHouse3   | 4            | 1           |
+------------+--------------+-------------+

Products 表:
+------------+--------------+------------+----------+-----------+
| product_id | product_name | Width      | Length   | Height    |
+------------+--------------+------------+----------+-----------+
| 1          | LC-TV        | 5          | 50       | 40        |
| 2          | LC-KeyChain  | 5          | 5        | 5         |
| 3          | LC-Phone     | 2          | 10       | 10        |
| 4          | LC-T-Shirt   | 4          | 10       | 20        |
+------------+--------------+------------+----------+-----------+

Result 表:
+----------------+------------+
| WAREHOUSE_NAME | VOLUME     | 
+----------------+------------+
| LCHouse1       | 12250      | 
| LCHouse2       | 20250      |
| LCHouse3       | 800        |
+----------------+------------+
Id为1的商品(LC-TV)的存货量为 5x50x40 = 10000
Id为2的商品(LC-KeyChain)的存货量为 5x5x5 = 125 
Id为3的商品(LC-Phone)的存货量为 2x10x10 = 200
Id为4的商品(LC-T-Shirt)的存货量为 4x10x20 = 800
仓库LCHouse1: 1个单位的LC-TV + 10个单位的LC-KeyChain + 5个单位的LC-Phone.
          总存货量为: 1*10000 + 10*125  + 5*200 = 12250 立方英尺
仓库LCHouse2: 2个单位的LC-TV + 2个单位的LC-KeyChain.
          总存货量为: 2*10000 + 2*125 = 20250 立方英尺
仓库LCHouse3: 1个单位的LC-T-Shirt.
          总存货量为: 1*800 = 800 立方英尺.

解法

Python3

Java

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