Skip to content

Latest commit

 

History

History
119 lines (51 loc) · 1.91 KB

File metadata and controls

119 lines (51 loc) · 1.91 KB

中文文档

Description

Table: Employees

+-------------+---------+

| Column Name | Type    |

+-------------+---------+

| employee_id | int     |

| name        | varchar |

| salary      | int     |

+-------------+---------+

employee_id is the primary key for this table.

Each row of this table indicates the employee ID, employee name, and salary.

 

Write an SQL query to calculate the bonus of each employee. The bonus of an employee is 100% of their salary if the ID of the employee is an odd number and the employee name does not start with the character 'M'. The bonus of an employee is 0 otherwise.

Return the result table ordered by employee_id.

The query result format is in the following example:

 

Employees table:

+-------------+---------+--------+

| employee_id | name    | salary |

+-------------+---------+--------+

| 2           | Meir    | 3000   |

| 3           | Michael | 3800   |

| 7           | Addilyn | 7400   |

| 8           | Juan    | 6100   |

| 9           | Kannon  | 7700   |

+-------------+---------+--------+



Result table:

+-------------+-------+

| employee_id | bonus |

+-------------+-------+

| 2           | 0     |

| 3           | 0     |

| 7           | 7400  |

| 8           | 0     |

| 9           | 7700  |

+-------------+-------+



The employees with IDs 2 and 8 get 0 bonus because they have an even employee_id.

The employee with ID 3 gets 0 bonus because their name starts with 'M'.

The rest of the employees get a 100% bonus.

Solutions

SQL