[최단 경로] 2171064 문하영 #354
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[최단 경로] 2171064 문하영 #354
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코드리뷰완료 |
Dong-droid
reviewed
May 31, 2023
| graph[s].push_back({e, T}); | ||
| } | ||
| //연산 | ||
| vector<int> dist_x = dijkstra(x, n, graph); //최단 시간 저장 |
Dong-droid
reviewed
May 31, 2023
Comment on lines
+55
to
+59
| for (int i = 1; i <= n; i++) { | ||
| vector<int> dist_i = dijkstra(i, n, graph); // i -> X의의 최단 시간 | ||
| max_T = max(max_T, dist_x[i] + dist_i[x]); //max_T 갱신 | ||
| } | ||
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Dong-droid
reviewed
May 31, 2023
Comment on lines
+39
to
+54
| //출력 | ||
| int ans = 0; | ||
| for(int i=1; i<=N; i++){ | ||
| bool flag = true; | ||
| for(int j=1; j<=N; j++){ | ||
| if(i == j) continue; | ||
| else if(graph[i][j] == INF && graph[j][i] == INF){ | ||
| flag = false; //i와 j 사이의 가중치가 없는 경우 | ||
| break; | ||
| } | ||
| } | ||
| if(flag) { | ||
| ans++; | ||
| } | ||
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|
||
| } |
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P3. else if 일 필요는 없을 것 같아요. 앞에서 continue;이니까 if만 써줘도 될 것 같아요~
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인적사항
학번: 2171064
이름: 문하영
과제 제출
기존 제출 : 1238, 2458
추가 제출 : 15685