Ensure that "true" and "false" won't go in same bucket in hash table

Previously, "hash true" and "hash false" were both congruent to 1 (mod
4).  We just set them to 1 and 0, resp.

Also update the corresponding basic test.

M2/Macaulay2/d/basic.d

@@ -11,7 +11,7 @@ export hash(e:Expr):hash_t := (
      is s:SymbolBody do s.symbol.hash
      is x:Database do x.hash
      is x:ZZcell do hash(x.v)
-     is b:Boolean do if b.v then hash_t(444777) else hash_t(777333)
+     is b:Boolean do Ccode(hash_t, b.v)
      is Nothing do hash_t(333889)
      is x:List do x.hash
      is f:functionCode do f.hash

M2/Macaulay2/m2/basictests/hashcodes.m2

@@ -11,15 +11,13 @@ assert( (hash (1,2,3)) === 568179786079386623 )
 assert( (hash [1,2,3]) === 9684772971066268688 )
 assert( (hash (3/5)) === 6499208 )
 assert( (hash new HashTable from { 1 => 2 , 3 => 4 }) === 14342786426447859 )
-assert( (hash true) === 444777 )
-assert( (hash false) === 777333 )
+assert( (hash true) === 1 )
+assert( (hash false) === 0 )
 assert( (hash null) === 333889 )
 assert( (hash Nothing) === 1000069 )
 assert( (hash (1 => 2)) === 1729140528276943882 )
 assert( hash Nothing == 1000069 )
 assert( (hash Boolean) === 1000035 )
-assert( (hash true) === 444777 )
-assert( (hash false) === 777333 )
 
 -- these might change if our floating point implementation changes, but let's check anyway:
 assert( hash 1.23p200 === 18446744072207201388 -* 64-bit *- or hash 1.23p200 == 18446744073069319069 -* 32-bit *- )