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btrfs: don't start transaction for scrub if the fs is mounted read-only
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[BUG]
The following super simple script would crash btrfs at unmount time, if
CONFIG_BTRFS_ASSERT() is set.

 mkfs.btrfs -f $dev
 mount $dev $mnt
 xfs_io -f -c "pwrite 0 4k" $mnt/file
 umount $mnt
 mount -r ro $dev $mnt
 btrfs scrub start -Br $mnt
 umount $mnt

This will trigger the following ASSERT() introduced by commit
0a31daa ("btrfs: add assertion for empty list of transactions at
late stage of umount").

That patch is definitely not the cause, it just makes enough noise for
developers.

[CAUSE]
We will start transaction for the following call chain during scrub:

  scrub_enumerate_chunks()
  |- btrfs_inc_block_group_ro()
     |- btrfs_join_transaction()

However for RO mount, there is no running transaction at all, thus
btrfs_join_transaction() will start a new transaction.

Furthermore, since it's read-only mount, btrfs_sync_fs() will not call
btrfs_commit_super() to commit the new but empty transaction.

And leads to the ASSERT().

The bug has been there for a long time. Only the new ASSERT() makes it
noisy enough to be noticed.

[FIX]
For read-only scrub on read-only mount, there is no need to start a
transaction nor to allocate new chunks in btrfs_inc_block_group_ro().

Just do extra read-only mount check in btrfs_inc_block_group_ro(), and
if it's read-only, skip all chunk allocation and go inc_block_group_ro()
directly.

CC: [email protected] # 5.4+
Signed-off-by: Qu Wenruo <[email protected]>
Signed-off-by: David Sterba <[email protected]>
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adam900710 authored and kdave committed Jan 31, 2022
1 parent 27cdfde commit 2d192fc
Showing 1 changed file with 13 additions and 0 deletions.
13 changes: 13 additions & 0 deletions fs/btrfs/block-group.c
Original file line number Diff line number Diff line change
Expand Up @@ -2544,6 +2544,19 @@ int btrfs_inc_block_group_ro(struct btrfs_block_group *cache,
int ret;
bool dirty_bg_running;

/*
* This can only happen when we are doing read-only scrub on read-only
* mount.
* In that case we should not start a new transaction on read-only fs.
* Thus here we skip all chunk allocations.
*/
if (sb_rdonly(fs_info->sb)) {
mutex_lock(&fs_info->ro_block_group_mutex);
ret = inc_block_group_ro(cache, 0);
mutex_unlock(&fs_info->ro_block_group_mutex);
return ret;
}

do {
trans = btrfs_join_transaction(root);
if (IS_ERR(trans))
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