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btrfs: don't start transaction for scrub if the fs is mounted read-only
commit 2d192fc upstream. [BUG] The following super simple script would crash btrfs at unmount time, if CONFIG_BTRFS_ASSERT() is set. mkfs.btrfs -f $dev mount $dev $mnt xfs_io -f -c "pwrite 0 4k" $mnt/file umount $mnt mount -r ro $dev $mnt btrfs scrub start -Br $mnt umount $mnt This will trigger the following ASSERT() introduced by commit 0a31daa ("btrfs: add assertion for empty list of transactions at late stage of umount"). That patch is definitely not the cause, it just makes enough noise for developers. [CAUSE] We will start transaction for the following call chain during scrub: scrub_enumerate_chunks() |- btrfs_inc_block_group_ro() |- btrfs_join_transaction() However for RO mount, there is no running transaction at all, thus btrfs_join_transaction() will start a new transaction. Furthermore, since it's read-only mount, btrfs_sync_fs() will not call btrfs_commit_super() to commit the new but empty transaction. And leads to the ASSERT(). The bug has been there for a long time. Only the new ASSERT() makes it noisy enough to be noticed. [FIX] For read-only scrub on read-only mount, there is no need to start a transaction nor to allocate new chunks in btrfs_inc_block_group_ro(). Just do extra read-only mount check in btrfs_inc_block_group_ro(), and if it's read-only, skip all chunk allocation and go inc_block_group_ro() directly. CC: [email protected] # 5.4+ Signed-off-by: Qu Wenruo <[email protected]> Signed-off-by: David Sterba <[email protected]> Signed-off-by: Greg Kroah-Hartman <[email protected]>
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