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Fixed typo
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fessur committed Jun 18, 2023
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2 changes: 1 addition & 1 deletion tex/question26.tex
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Expand Up @@ -35,7 +35,7 @@ \section{Неравенство Чебышева для определенных
Получили
\[ 0 \leq E_{fg} - f\left( y\right)E_g-g \left( y\right)E_f+ f\left( y\right)g \left( y\right)\]

Теперь "разморозим" \( y\) и проинтегрируем левую часть получившегося неравенства по \( y\):
Теперь "разморозим" \( y\) и проинтегрируем правую часть получившегося неравенства по \( y\):
\begin{equation*}
\begin{aligned}
0 &\leq \displaystyle\int\limits_{ a}^{ b} E_{fg} - f\left( y\right)E_g-g \left( y\right)E_f+ f\left( y\right)g \left( y\right) dy =\\
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2 changes: 1 addition & 1 deletion tex/question50.tex
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Expand Up @@ -33,7 +33,7 @@ \section{Теорема о группировке членов ряда.}
\begin{equation*}
\begin{aligned}
&\left| S_n-S\right|=\left| S_n-S_{n_j}+S_{n_j}-S\right| \leq \left| S_n-S_{n_j}\right|+\left| S_{n_j}-S\right|= \left|\sum\limits_{ k=n_{j}+1}^{ n} a_k \right| + \left| S_{n_j}-S\right| \leq \\
& \leq \sum\limits_{ k=n{j}+1}^{ n} \left| a_k\right| + \left| S_{n_j}-S\right| < N\cdot \dfrac{ \varepsilon}{ 2N} + \dfrac{ \varepsilon}{ 2} = \varepsilon
& \leq \sum\limits_{ k=n_{j}+1}^{ n} \left| a_k\right| + \left| S_{n_j}-S\right| < N\cdot \dfrac{ \varepsilon}{ 2N} + \dfrac{ \varepsilon}{ 2} = \varepsilon
\end{aligned}
\end{equation*}
\par Получается \( \forall \; \varepsilon >0\quad \exists \; \tilde{ N}=n_i+1:\quad \forall \; n \geq \tilde{ N}\quad \left| S_n-S\right|< \varepsilon \Longrightarrow S_n \longrightarrow S\)
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