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Improved task 857
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javadev authored Mar 31, 2023
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Expand Up @@ -1719,7 +1719,7 @@ implementation 'com.github.javadev:leetcode-in-kotlin:1.11'
| 1143 |[Longest Common Subsequence](src/main/kotlin/g1101_1200/s1143_longest_common_subsequence/Solution.kt)| Medium | Top_100_Liked_Questions, String, Dynamic_Programming, Algorithm_II_Day_17_Dynamic_Programming, Dynamic_Programming_I_Day_19, Udemy_Dynamic_Programming | 307 | 38.36
| 0994 |[Rotting Oranges](src/main/kotlin/g0901_1000/s0994_rotting_oranges/Solution.kt)| Medium | Array, Breadth_First_Search, Matrix, Algorithm_I_Day_9_Breadth_First_Search_Depth_First_Search, Level_2_Day_10_Graph/BFS/DFS | 308 | 57.93
| 0864 |[Shortest Path to Get All Keys](src/main/kotlin/g0801_0900/s0864_shortest_path_to_get_all_keys/Solution.kt)| Hard | Breadth_First_Search, Bit_Manipulation | 176 | 100.00
| 0857 |[Score of Parentheses](src/main/kotlin/g0801_0900/s0857_minimum_cost_to_hire_k_workers/Solution.kt)| Hard | Array, Sorting, Greedy, Heap_Priority_Queue | 302 | 100.00
| 0857 |[Minimum Cost to Hire K Workers](src/main/kotlin/g0801_0900/s0857_minimum_cost_to_hire_k_workers/Solution.kt)| Hard | Array, Sorting, Greedy, Heap_Priority_Queue | 302 | 100.00
| 0856 |[Score of Parentheses](src/main/kotlin/g0801_0900/s0856_score_of_parentheses/Solution.kt)| Medium | String, Stack | 129 | 84.62
| 0855 |[Exam Room](src/main/kotlin/g0801_0900/s0855_exam_room/ExamRoom.kt)| Medium | Design, Ordered_Set | 644 | 83.33
| 0854 |[K-Similar Strings](src/main/kotlin/g0801_0900/s0854_k_similar_strings/Solution.kt)| Hard | String, Breadth_First_Search | 136 | 100.00
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856\. Score of Parentheses
857\. Minimum Cost to Hire K Workers

Medium
Hard

Given a balanced parentheses string `s`, return _the **score** of the string_.
There are `n` workers. You are given two integer arrays `quality` and `wage` where `quality[i]` is the quality of the <code>i<sup>th</sup></code> worker and `wage[i]` is the minimum wage expectation for the <code>i<sup>th</sup></code> worker.

The **score** of a balanced parentheses string is based on the following rule:
We want to hire exactly `k` workers to form a paid group. To hire a group of `k` workers, we must pay them according to the following rules:

* `"()"` has score `1`.
* `AB` has score `A + B`, where `A` and `B` are balanced parentheses strings.
* `(A)` has score `2 * A`, where `A` is a balanced parentheses string.
1. Every worker in the paid group should be paid in the ratio of their quality compared to other workers in the paid group.
2. Every worker in the paid group must be paid at least their minimum wage expectation.

**Example 1:**
Given the integer `k`, return _the least amount of money needed to form a paid group satisfying the above conditions_. Answers within <code>10<sup>-5</sup></code> of the actual answer will be accepted.

**Input:** s = "()"
**Example 1:**

**Output:** 1
**Input:** quality = [10,20,5], wage = [70,50,30], k = 2

**Example 2:**
**Output:** 105.00000

**Input:** s = "(())"
**Explanation:** We pay 70 to 0<sup>th</sup> worker and 35 to 2<sup>nd</sup> worker.

**Output:** 2
**Example 2:**

**Example 3:**
**Input:** quality = [3,1,10,10,1], wage = [4,8,2,2,7], k = 3

**Input:** s = "()()"
**Output:** 30.66667

**Output:** 2
**Explanation:** We pay 4 to 0<sup>th</sup> worker, 13.33333 to 2<sup>nd</sup> and 3<sup>rd</sup> workers separately.

**Constraints:**

* `2 <= s.length <= 50`
* `s` consists of only `'('` and `')'`.
* `s` is a balanced parentheses string.
* `n == quality.length == wage.length`
* <code>1 <= k <= n <= 10<sup>4</sup></code>
* <code>1 <= quality[i], wage[i] <= 10<sup>4</sup></code>

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