Test if BigInt instance is a finite number #34
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Rudxain
reviewed
Oct 4, 2024
| return finite(+num); | ||
| } | ||
| if (typeof num === 'bigint') { | ||
| return finite(Number(num)) |
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the "finite" function (Number.isFinite) will check whether the output is a value that can be represented by a Javascript number. The return value will be a Boolean.
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I'm sorry, I wasn't clear. I meant that BigInts could always be considered as "valid numerical values" (as in math), not necessarily "all BigInts are valid Numbers, because they never coerce to NaN"
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Wait, now that I think about it, that should be a separate function named isNumeric
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Yeah, probably.
Anyway I don't think this changeset is getting merged (almost three years old 🍰)
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BigInt can represent a value that can be represented by a number or larger.
This now checks if it is representing a value that can be represented by a Javascript number.
Disclosure: There's a performance hit for non-string or numbers. Others are obviously not affected
