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Create RotateArray.java #149
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/****************************************************************************** | ||
189.) Rotate Array | ||
Difficulty: Medium | ||
Description: Given an array, rotate the array to the right by k steps, where k is non-negative. | ||
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Naive Approach: Create a function that rotates the array onces, then rotate the array k times. | ||
Efficient Approach: Reverse the whole list, then reverse the first k elements, and the last n - k elements. | ||
*******************************************************************************/ | ||
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public class RotateArray | ||
{ | ||
public static void main(String[] args) { | ||
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/* This is the test, expected output is [4,5,1,2,3] */ | ||
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int [] arr = {1,2,3,4,5}; | ||
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rotate(arr, 2); | ||
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int[] rotate_arr = arr; | ||
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for(int i = 0; i < rotate_arr.length; i++){ | ||
System.out.print(rotate_arr[i] + " "); | ||
} | ||
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} | ||
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public static void rotate(int[] nums, int k) { | ||
k = k % nums.length; | ||
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reverse(nums, 0, nums.length - 1); | ||
reverse(nums, 0, k-1); | ||
reverse(nums, k, nums.length - 1); | ||
} | ||
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public static int [] reverse(int [] nums, int start, int end){ | ||
int indx_end = end, indx_start = start; | ||
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while(indx_start < indx_end){ | ||
int temp = nums[indx_start]; | ||
nums[indx_start] = nums[indx_end]; | ||
nums[indx_end] = temp; | ||
indx_start++; | ||
indx_end--; | ||
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} | ||
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return nums; | ||
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} | ||
} | ||
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The alternative solution
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Both solution are correct