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Chapter 1 #520
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Chapter 1 #520
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@@ -209,31 +209,31 @@ So, the output in this example means that 'False' has type 'Bool'. | |
> Try to guess first and then compare your expectations with GHCi output | ||
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>>> :t True | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
True :: Bool | ||
>>> :t 'a' | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
'a' :: Char | ||
>>> :t 42 | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
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42 :: Num p => p | ||
A pair of boolean and char: | ||
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>>> :t (True, 'x') | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
(True, 'x') :: (Bool Char) | ||
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Boolean negation: | ||
>>> :t not | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
not : Bool -> Bool | ||
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Boolean 'and' operator: | ||
>>> :t (&&) | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
(&&) :: Bool -> Bool -> Bool | ||
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Addition of two numbers: | ||
>>> :t (+) | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
(+) :: Num a => a -> a -> a | ||
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Maximum of two values: | ||
>>> :t max | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
max :: Ord a => a -> a -> a | ||
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You might not understand each type at this moment, but don't worry! You've only | ||
started your Haskell journey. Types will become your friends soon. | ||
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@@ -301,43 +301,43 @@ expressions in GHCi | |
functions and operators first. Remember this from the previous task? ;) | ||
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>>> 1 + 2 | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
3 | ||
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>>> 10 - 15 | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
-5 | ||
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>>> 10 - (-5) -- negative constants require () | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
15 | ||
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>>> (3 + 5) < 10 | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
True | ||
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>>> True && False | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
False | ||
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>>> 10 < 20 || 20 < 5 | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
True | ||
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>>> 2 ^ 10 -- power | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
1024 | ||
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>>> not False | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
True | ||
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>>> div 20 3 -- integral division | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
6 | ||
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>>> mod 20 3 -- integral division remainder | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
2 | ||
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>>> max 4 10 | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
10 | ||
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>>> min 5 (max 1 2) | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
2 | ||
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>>> max (min 1 10) (min 5 7) | ||
<INSERT THE RESULT INSTEAD OF THE TEXT> | ||
5 | ||
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Because Haskell is a __statically-typed__ language, you see an error each time | ||
you try to mix values of different types in situations where you are not | ||
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@@ -428,7 +428,7 @@ task is to specify the type of this function. | |
>>> squareSum 3 4 | ||
49 | ||
-} | ||
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squareSum :: Int -> Int -> Int | ||
squareSum x y = (x + y) * (x + y) | ||
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@@ -449,7 +449,7 @@ Implement the function that takes an integer value and returns the next 'Int'. | |
function body with the proper implementation. | ||
-} | ||
next :: Int -> Int | ||
next x = error "next: not implemented!" | ||
next x = x + 1 | ||
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{- | | ||
After you've implemented the function (or even during the implementation), you | ||
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@@ -490,7 +490,8 @@ Implement a function that returns the last digit of a given number. | |
whether it works for you! | ||
-} | ||
-- DON'T FORGET TO SPECIFY THE TYPE IN HERE | ||
lastDigit n = error "lastDigit: Not implemented!" | ||
lastDigit :: Int -> Int | ||
lastDigit x = mod x 10 | ||
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{- | | ||
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@@ -520,7 +521,7 @@ branches because it is an expression and it must always return some value. | |
satisfying the check will be returned and, therefore, evaluated. | ||
-} | ||
closestToZero :: Int -> Int -> Int | ||
closestToZero x y = error "closestToZero: not implemented!" | ||
closestToZero x y = if abs x > abs y then y else x | ||
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{- | | ||
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@@ -553,8 +554,11 @@ value after "=" where the condition is true. | |
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Casual reminder about adding top-level type signatures for all functions :) | ||
-} | ||
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mid x y z = error "mid: not implemented!" | ||
mid :: Int -> Int -> Int -> Int | ||
mid x y z | ||
| x < y && y < z = y | ||
| y < z && z < x = z | ||
| otherwise = x | ||
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{- | | ||
=⚔️= Task 8 | ||
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@@ -568,7 +572,15 @@ True | |
>>> isVowel 'x' | ||
False | ||
-} | ||
isVowel c = error "isVowel: not implemented!" | ||
isVowel :: Char -> Bool | ||
isVowel c | ||
| c == 'a' || c == 'A' = True | ||
| c == 'e' || c == 'E'= True | ||
| c == 'i' || c == 'I' = True | ||
| c == 'o' || c == 'I' = True | ||
| c == 'u' || c == 'O' = True | ||
| otherwise = False | ||
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{- | | ||
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@@ -631,9 +643,15 @@ Implement a function that returns the sum of the last two digits of a number. | |
Try to introduce variables in this task (either with let-in or where) to avoid | ||
specifying complex expressions. | ||
-} | ||
sumLast2 :: Int -> Int | ||
sumLast2 n = let last = mod n 10 | ||
seclast = mod (div n 10) 10 -- div n 10 gives the digit stripped off last digit. | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. That is a wonderful solution! 👏🏼 You correctly noticed that it is the One hint to make your solution even shorter: you can see that you use both: mod m 10
div m 10 The standard library has the So you could write it this way: (x, y) = divMod m 10 You can see how we could pattern match on the pair 🙂 |
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in last + seclast | ||
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sumLast2 n = error "sumLast2: Not implemented!" | ||
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sumLast2' :: Int -> Int | ||
sumLast2' n = last + seclast where | ||
last = mod n 10 | ||
seclast = mod (div n 10) 10 | ||
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{- | | ||
=💣= Task 10* | ||
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@@ -653,8 +671,8 @@ You need to use recursion in this task. Feel free to return to it later, if you | |
aren't ready for this boss yet! | ||
-} | ||
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firstDigit n = error "firstDigit: Not implemented!" | ||
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firstDigit :: Int -> Int | ||
firstDigit n = if n < 10 then n else firstDigit (div n 10) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I see, that for a negative number like -19, this implementation will return the negative number itself instead of the last digit because the first check n < 10 will always succeed for negative numbers. |
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{- | ||
You did it! Now it is time to open a pull request with your changes | ||
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Your implementation is almost correct 🆗
Unfortunately, it returns negative numbers on negative inputs because of how
mod
works. Sometimes corner cases can be tricky to spot and fix...