Solution for task 1.3 #27
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boroda4436
suggested changes
Aug 20, 2019
| return number; | ||
| } | ||
| count++; | ||
| } while (exponential > count); |
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too complex. Lets do it with for loop
4MoPDai
commented
Aug 20, 2019
boroda4436
suggested changes
Aug 20, 2019
| int result = number; | ||
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| for (int i = 1; i < exponential; i++) { | ||
| if (exponential == 0) { |
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@4MoPDai Maybe it will be better to move this if out from the loop? If exponential == 0 how you will go over the loop?
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I've added a new function for solution task 1.3