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Spring JPA with Play!
peterszatmary edited this page Feb 21, 2016
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4 revisions
db.default.jndiName="someJndiName"
jpa.default="someJpaName"
<non-jta-data-source>someJndiName</non-jta-data-source>
<persistence-unit name="someJpaName" transaction-type="RESOURCE_LOCAL">
libraryDependencies ++= Seq(
javaCore,
javaJpa,
"org.springframework" % "spring-context" % "4.1.6.RELEASE",
"javax.inject" % "javax.inject" % "1",
"org.springframework.data" % "spring-data-jpa" % "1.3.2.RELEASE",
"org.springframework" % "spring-expression" % "4.1.6.RELEASE",
"mysql" % "mysql-connector-java" % "5.1.18",
db.default.driver=com.mysql.jdbc.Driver
db.default.url="jdbc:mysql://localhost:3306/test"
db.default.user=root
db.default.pass="anarchitekt"
db.default.jndiName=DefaultDS
jpa.default=defaultPersistenceUnit
logger.play=INFO
logger.org.springframework=TRACE
<persistence-unit name="defaultPersistenceUnit" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<non-jta-data-source>DefaultDS</non-jta-data-source>
<properties>
<!-- dialect for a MYSQL database -->
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect"/>
<property name="hibernate.hbm2ddl.auto" value="update"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.format_sql" value="true"/>
</properties>