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E-Mail-Check-Lösung von gtuthey hinzugefügt
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wiefling committed Feb 2, 2022
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MIT License

Copyright (c) 2022 gtuthey
Copyright (c) 2018 Luigi Lo Iacono, Stephan Wiefling, Michael Schneider

Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:

The above copyright notice and this permission notice shall be included in all
copies or substantial portions of the Software.

THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
SOFTWARE.
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def isEmail (email_address):
# finde das @ und den ersten . nach dem @
at = email_address.find("@")
dot = email_address.find(".",at)

# identifiziere die drei relevanten Teile der Adresse
prefix = email_address[0:at]
domain_name = email_address[at+1:dot]
suffix = email_address[dot+1:]

# Prüfe die Email-Teile
return len(prefix) > 1 and len(domain_name) >1 and domain_name.find("@") == -1 and (0 < len(suffix) <4)

# Hauptprogramm
print(isEmail("[email protected]"))
print(isEmail("[email protected]"))
print(isEmail("[email protected]"))
print(isEmail("@.net"))
print(isEmail("[email protected]"))

# akzeptiert auch Emails, mit einem '.' vor dem '@'
print(isEmail("[email protected]"))

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