[TEST] Small correction in binning_bitvector_benchmark #76
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To determine the number of words,
(bitvector.size() + 63u) >> 6is more correct thanbitvector.size() >> 6.The
binning_bitvectorcan have a size that is not a multiple of 64; currently, the IBF can be constructed with an arbitrary bin count. However, any unused bits in this case are always0.