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changing the hint at 19% #480

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changing the hint at 19% #480

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2 changes: 1 addition & 1 deletion Statistical_Inference/ConditionalProbability/lesson
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Original file line number Diff line number Diff line change
Expand Up @@ -47,7 +47,7 @@
AnswerChoices: (1/6)/(1/2); (1/2)/(1/6); (1/3)/(1/2); 1/6
CorrectAnswer: (1/6)/(1/2)
AnswerTests: omnitest(correctVal='(1/6)/(1/2)')
Hint: Here A is a subset of B so the probability of both A AND B happening is the probability of A happening. The probability of B is the reciprocal of the number of odd numbers between 1 and 6 (inclusive).
Hint: Here A is a subset of B so the probability of both A AND B happening is the probability of A happening. The probability of B is the probability of an odd number occurring.

- Class: text
Output: From the definition of P(A|B), we can write P(A&B) = P(A|B) * P(B), right? Let's use this to express P(B|A).
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