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Python function that performs a balanced cut-tree of a SciPy linkage matrix

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A balanced tree cut method for hierarchical clustering

This repo (and PyPI package) contains a Python function that performs a balanced cut-tree of a SciPy linkage matrix built using any linkage method (e.g. 'ward'). It builds upon the SciPy and NumPy libraries.

The initial problem was the following: if you perform a standard cut on a tree (i.e. the result from a hierarchical clustering), probably you will end up having a few big clusters (where the number of data samples is high), and many small clusters (each containing very few data samples). Thus, the resulting clustering is unbalanced, i.e. it contains clusters of very variable size.

The proposed function looks recursively along the hierarchical tree, from the root (single cluster gathering all the samples) to the leaves (i.e. the clusters with only one sample), retrieving the biggest possible clusters containing a number of samples lower than a given maximum. In this way, if a cluster at a specific tree level contains a number of samples higher than the given maximum, it is ignored and its offspring (smaller) sub-clusters are taken into consideration. If the cluster contains a number of samples lower than the given maximum, it is taken as result and its offspring sub-clusters not further processed.

Since all output clusters contain no more than a given maximum number of samples, the resulting clustering is considered to be more balanced than a standard cut-tree. Note however that the number of samples per cluster might still have a considerable variability, since the splitting of a big cluster can result in sub-clusters with very variable number of samples. This variability should be smaller as the given maximum of samples per cluster is closer to 1 (being the variability equal to 0 when the maximum is at its limit, i.e. 1).

The function returns two results:

  1. List of integers containing for each input sample its corresponding cluster id. The cluster id is an integer which is higher for deeper tree levels.
  2. List of integer arrays containing for each input sample its corresponding cluster tree level, i.e. a sequence of 0s and 1s. Note that the cluster level is longer for deeper tree levels, being [0] the root cluster, [0, 0] and [0, 1] its offspring, and so on. Also note that in each cluster splitting, the label 0 denotes the bigger cluster, while the label 1 denotes the smallest.

Installation and Use

This package can be installed using pip.

$ pip install scipy_cut_tree_balanced

Then you can use the function as shown in this sample Python code.

from scipy_cut_tree_balanced import cut_tree_balanced

from scipy.cluster.hierarchy import linkage
from scipy.stats import gamma
import numpy as np


# Initialize the random seed
np.random.seed(14)

# Create a input matrix containing 100 data samples with 4 dimensions
X = gamma.rvs(0.1, size=400).reshape((100, 4))

# Compute the linkage matrix using the scipy linkage() method
Z = linkage(X, 'ward')

# Perform a balanced cut-tree of the linkage matrix
[balanced_cut_cluster_id, balanced_cut_cluster_level] = cut_tree_balanced(Z, 10)

print("First 10 rows of the balanced clustering result (one cluster id per sample):")
print(str(balanced_cut_cluster_id[0:10]) + " ...")

Example Script

By running example.py you will get more elaborate printed outputs similar to the following. Here we perform a more detailed comparison between a standard and a balanced cut-tree.

$ python3 example.py

First, a numpy array of 100 rows x 4 columns is randomly generated using a gamma distribution. Note that we perform such a random sampling from a gamma distribution so that the resulting standard clustering is unbalanced (see below).

    np.random.seed(4)
    X = gamma.rvs(0.1, size=400).reshape((100,4))

In order to check the validity of the input data, the type, shape and the first 10 rows are printed.

Type of the input data sample: <class 'numpy.ndarray'>
Shape of the input data sample: (100, 4)
First 10 rows of the input data:
[[1.28573793e-03 8.12672961e-06 1.26520704e-03 2.07729574e-03]
 [1.16397414e-01 2.06534197e-03 1.91044478e-02 5.35127859e-01]
 [5.81563428e-02 5.92302950e-06 1.90433024e-02 2.87155777e-02]
 [3.98932109e-08 5.37862343e-02 4.38562255e-02 1.27557329e-04]
 [3.57028885e-04 2.88945299e-05 3.40388733e-05 9.90278888e-06]
 [3.91282036e-06 4.61803593e-02 2.75652111e-08 1.66504104e-09]
 [2.60630428e-10 3.89770028e-04 8.52159994e-03 5.83321506e-09]
 [6.37325763e-10 3.41859809e-04 4.51815091e-02 2.83600476e-06]
 [1.14654357e-03 1.12808821e-02 1.61202749e-04 1.56459197e-11]]

Next, the linkage matrix is computed by using the ward method, and a standard cut-tree is performed (with a specific number of output clusters = 20).

    Z = linkage(X, 'ward')
    standard_cut_cluster_id = cut_tree(Z, n_clusters=[20])

As shown below, the output is a numpy array of 100 elements, assigning one cluster ID to each input vector (of 4 dimensions, see above). Note that the ID of the resulting clusters go from 0 to 19 in this case. The resulting clustering is unbalanced, i.e. containing a big cluster (where the number of data samples is 48), and many small clusters (each containing very few data samples, 9 of them containing a single data sample). As result, the range of cluster sizes goes from 1 to 48, showing a standard deviation of 10.17 data samples.

Type of the standard clustering result: <class 'numpy.ndarray'>
Shape of the standard clustering result (one cluster id per data sample): (100, 1)
First 10 rows of the standard clustering result (one cluster id per sample):
[0 1 0 0 0 0 0 0 0 2] ...
Total number of resulting clusters = 20
For each resulting cluster: Cluster ID
[ 0  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15 16 17 18 19]
For each resulting cluster: Count of data samples
[48  4  1  2 10  8  1  6  2  2  1  1  1  1  3  1  4  2  1  1]
Count of data samples per cluster: mean = 5, max = 48, min = 1, std = 10.17

The following figure illustrates visually the resulting clustering by using the standard cut-tree. The black line shows the height at which the cut (i.e. pruning) is performed (which is identical for all clusters). The resulting cluster IDs are depicted within the black squares (i.e. numbers in white represent the obtained cluster IDs). As result, the cluster ID 0 contains 48 elements (almost half of the data samples), an issue which we try to address with our proposed method.

Dendrogram Standard Cut

A more balanced clustering is then attempted by using the balanced ward tree method, in which the maximum number of data samples within each cluster is set to 10.

    [balanced_cut_cluster_id, balanced_cut_cluster_level] = cut_tree_balanced(Z, 10)

We get two results from the new function: (1) a list of integers containing for each input sample its corresponding cluster id, and (2) a list containing for each input sample its corresponding cluster tree level (represented by a sequence of 0s and 1s, see above first section for further information). Note that the ID of the resulting clusters go again from 0 to 19 in this case, i.e. the number of resulting clusters (20) is identical to the previous one. Importantly, the resulting clustering is more balanced than the standard one (for an equal number of resulting clusters), since the range of cluster sizes goes from 1 to 10, showing a standard deviation of 2.68 data samples.

Type of the balanced clustering result (id): <class 'numpy.ndarray'>
Shape of the balanced clustering result (one cluster id per data sample): (100,)
First 10 rows of the balanced clustering result (one cluster id per sample):
[18  3  9 11 19 11 13  8 14  1] ...

Type of the balanced clustering result (level): <class 'numpy.ndarray'>
Shape of the balanced clustering result (level) (one array per data sample): (100,)
First 10 rows of the balanced clustering result (level) (one array per sample):
[array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1])
 array([0, 0, 0, 1])
 array([0, 0, 0, 0, 0, 0, 0, 0, 1])
 array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1])
 array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0])
 array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1])
 array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1])
 array([0, 0, 0, 0, 0, 0, 0, 1])
 array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1])
 array([0, 0, 1, 0])] ...

Total number of resulting clusters = 20
For each resulting cluster: Cluster ID
[ 0  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15 16 17 18 19]
For each resulting cluster: Count of data samples
[ 2 10  2  7  7 10  6  8  8  3  4  4  3  3  3  1  4  3  4  8]
Count of data samples per cluster: mean = 5, max = 10, min = 1, std = 2.68

The following figure illustrates visually the resulting balanced clustering. Again, the resulting cluster IDs are depicted within the black squares (i.e. numbers in white represent the obtained cluster IDs). Now the tree level at which the clusters are selected (i.e. pruned) is different for each cluster ID, since the cluster search method is not only driven by the heigth (i.e. distance between clusters), but also by the number of samples contained within the clusters. Note for instance that cluster ID 0 is smaller (2 data samples) than cluster ID 16 (4 data samples), although the heigth at which it was pruned is much higher. As result, all clusters contain less or equal than a number of specific data samples (in this case 10), and therefore their size is less variable.

Dendrogram Balanced Cut

In conclusion, here we describe and implement a method which generates (for a similar number of resulting clusters) a more balanced outcome, i.e. building clusters of less variable size.

Note: the function dendogram from Scipy was used in order to generate the dendrograms shown in the exemplary figures. Cluster labels were drawn by choosing specific (x,y) coordinates, and tested for correctness in an iterative manner. Please note that there is no function available to plot the resulting dendograms and clustering labels automatically.

Searching for Optimal Parameter Max Cluster Size

A valid question is whether it is possible to perform some sort of hyperparameter optimization on max_cluster_size. This is very much related to the issue of determining the number of clusters in a dataset.

By running param_search.py you can perform a parameter search over two typical test datasets.

$ python3 param_search.py

To this purpose, the silhouette metric is used in order to quantify the fitness of the clustering configuration. In brief, it measures how similar a data sample is to its own cluster (cohesion) compared to other clusters (separation). The silhouette ranges from −1 to +1, where a high value indicates that the object is well matched to its own cluster.

For the Iris flower dataset (see also function sklearn.datasets.load_iris), we find that a max_cluster_size of 125 (resulting in 2 clusters) achieves the highest silhouette value (~0.72). This is the expected result, since the data set only contains two clusters with rather obvious separation. One of the clusters contains Iris setosa, while the other cluster contains both Iris virginica and Iris versicolor and is not separable without the species information (see the wikipedia site for further details).

For the Digits dataset (see also function sklearn.datasets.load_digits), we find that a max_cluster_size of 300 (resulting in 10 clusters) achieves the highest silhouette value (~0.18). This is as well the expected result, since images of 10 different hand-written digits are contained in this dataset.

In all, these outcomes confirm that a simple iterative parameter search algorigthm can be used in order to find the optimal value for max_cluster_size, and that the balanced tree cut method produces valid clustering results.

Citation in Papers

The DOI 10.5281/zenodo.4399514 (hosted by Zenodo) can be used in order to cite this software in academic papers.

DOI

The related BibTeX export is the following.

@software{vicente_reyes_puerta_2020_4399514,
  author       = {Vicente Reyes-Puerta},
  title        = {{A balanced tree cutting method for hierarchical
                   clustering}},
  month        = dec,
  year         = 2020,
  publisher    = {Zenodo},
  version      = {1.1},
  doi          = {10.5281/zenodo.4399514},
  url          = {https://doi.org/10.5281/zenodo.4399514}
}

Related Work

There are several implemented methods following the same or a similar idea, i.e. performing a cut-tree in which the resulting clusters are at different tree levels.

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Python function that performs a balanced cut-tree of a SciPy linkage matrix

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