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FliiFe committed Dec 29, 2021
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Expand Up @@ -35,7 +35,7 @@ \section{Définitions et propriétés de base}
\nu(\mathcal A)=\int_A f\diff \mu
\]
est une mesure complexe (notée $f\diff \mu$). Clairement, $\nu(\emptyset)=0$ et \[
\nu \left(\bigcup_{n \in \N}A_n)=\int_{X}f\diff \mu \1_{\bigcup A_i}=\int_{X}\sum_{n \in \N}\underbrace{f\1_{A_n}}_{\mathclap{\text{dominée par }|f|\text{ intégrable }}}\diff \mu = \sum_{n \in N}\int_{A_n} f\diff \mu=\sum_{n \in \N}\nu(A_n)
\nu \left(\bigcup_{n \in \N}A_n\right)=\int_{X}f\diff \mu \1_{\bigcup A_i}=\int_{X}\sum_{n \in \N}\underbrace{f\1_{A_n}}_{\mathclap{\text{dominée par }|f|\text{ intégrable }}}\diff \mu = \sum_{n \in N}\int_{A_n} f\diff \mu=\sum_{n \in \N}\nu(A_n)
\]
\end{ex}

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